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3 years ago

A circle with radius of 3cm sits inside a circle with radius of 11cm

Mathematics

1 answer:

sdas [7]3 years ago

6 0

Answer:

Circular shapes - They are those planner shapes that represent the locus of all the points that has a constant distance from a fixed point on the plane. This constant distance is termed as the radius of the circle and the fixed point is known as the center of the circle.

The center of the circle is enclosed by all the points on its periphery.

The circumference of the circle is the total length of its periphery around the center.

Concentric circles are two circles that have the same center

Step-by-step explanation:

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Given the exponential growth function f ( x ) = 75 ( 1.02 ) x f ( x ) = 75 ( 1.02 ) x What is the initial value of the function?

Anni [7]

Answer:

Step-by-step explanation:

The initial vale is when x = 0

- That is 75,

The growth factor is 2%.

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2 years ago

Subtract h + 3 from 6h + 1.

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the answer is 5h + 4

Step-by-step explanation:

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3 years ago

Find the product and fill in the blanks to write in standard complex number form.

solong [7]

Answer:

Step-by-step explanation:

Find the product and fill in the blanks to write in standard complex number form.

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3 years ago

Three collinear points on the coordinate plane are r(x,y), s(x+8h, y+8k), and p (x+6h, y+6k)

Karo-lina-s [1.5K]

Answer:

A. $\frac{RP}{SP}=3$

B. $\frac{RP}{RS}=\frac{3}{4}$

Step-by-step explanation:

The complete question is

Three collinear points on the coordinate plane are R(x, y), S(x+8h, y+8k), and P(x+6h, y+6k).

Part A: Determine the value of RP/SP

Part B: Determine the value of RP/RS

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$R(x,y),S(x+8h,y+8k) and P(x+6h,y+6k)$

Part A.We have to find the value of $\frac{RP}{SP}$

step 1

Find the distance RP

$R(x,y),P(x+6h,y+6k)$

substitute the values in the formula

$RP=\sqrt{(x+6h-x)^2+(y+6k-y)^2}$

$RP=\sqrt{36h^2+36 k^2}$

$RP=6\sqrt{h^2+k^2}$

step 2

Find the distance SP

$S(x+8h,y+8k),P(x+6h,y+6k)$

substitute the values in the formula

$SP=\sqrt{(x+6h-x-8h)^2+(y+6k-y-8k)^2}$

$SP=\sqrt{4h^2+4k^2}$

$SP=\sqrt{4(h^2+k^2)}$

$SP=2\sqrt{h^2+k^2}$

step 3

Find the ratio RP/SP

$\frac{RP}{SP}=\frac{6\sqrt{h^2+k^2}}{2\sqrt{h^2+k^2}}$

$\frac{RP}{SP}=3$

Part B. We have to determine the value of $\frac{RP}{RS}$

step 1

Find the distance RS

$R(x,y),S(x+8h,y+8k)$

$RS=\sqrt{(x+8h-x)^2+(y+8k-y)^2}$

$RS=\sqrt{64h^2+64k^2}$

$RS=\sqrt{64(h^2+k^2)}$

$RS=8\sqrt{h^2+k^2}$

step 2

Find the ratio RP/RS

$\frac{RP}{RS}=\frac{6\sqrt{h^2+k^2}}{8\sqrt{h^2+k^2}}$

$\frac{RP}{RS}=\frac{3}{4}$

5 0

3 years ago

2) What is the value of this collection of base ten blocks if the = 1?

Alex

Answer:

Step-by-step explanation:

So the single blocks are 1, the lines are 10, the single layer is 100 and the blocks are 1000. Let em know if you don't quite get that. But to find how many blocks are there in total we add each part.

1 block + 2 surfaces + 3 lines +6 single little blocks. that's one 1,000, two 100s, three 10s and six 1s or in other words 1,000 + 200 + 30 + 6 = 1,236

6 0

3 years ago