Answer:
-6s-c+1
Step-by-step explanation:
(-3s-4c+1)+(-3s+3c)
We have been given the above expression. To find the sum, we simply collect the like terms and combine them;
(-3s-4c+1)+(-3s+3c) = -3s + -3s -4c + 3c + 1
-3s + -3s -4c + 3c + 1 = -3s - 3s + 3c - 4c + 1
-3s - 3s + 3c - 4c + 1 = -6s - c + 1
Therefore;
(-3s-4c+1)+(-3s+3c) = -6s-c+1
By solving the linear equations we get the final values of x = 4 & y = 4.
What is the linear equation?
A linear equation is an algebraic equation of the form y=mx + b, where m is the slope and b is the y-intercept, and only a constant and a first-order term are included.
We have,
2x + 7y = -20 ----------(i)
x - 3y = 16 ----------(ii)
By multiplying equation (ii) with 2 we get,
2x + 7y = -20 ---------(III)
2x - 6y = 32 -----------(IV)
taking subtraction of equations (III) and (IV), we get
y = 4
by putting value of y in equation (ii) we get,
x = 4
Hence by solving the linear equations we get the values of x = 4 & y = 4.
To learn more about SAS similarity theorem visit,
brainly.com/question/1884491
#SPJ13
Answer:
The admission cost for each player was <u>22.50</u>.
Step-by-step explanation:
Given:
Luke’s basketball team went to an amusement park at the end of the season.
The cost of the admission for 5 coaches and 12 players was 407.50.
The admission cost for each coach was 27.50.
Now, to find the admission cost for each player.
Total admission cost = 407.50.
Number of coaches = 5.
Admission cost for each = 27.50.
So, the cost of admission of all coaches:
Then, we deduct the cost of admission of all coaches from the total admission cost:
<em>Remaining cost = 270.</em>
Number of player = 12.
Now, to get the admission cost for each player we divide the remaining cost by number of players:
Therefore, the admission cost for each player was 22.50.
Answer:
Differentiation
Step-by-step explanation:
Differentiation is used in only differential equations, finding limits and curve sketching.
..