Answer:
Lawns ---Earnings
1 ----------------- 10
2 ----------------- 20
3 ----------------- 30
5 ----------------- 50
Step-by-step explanation:
Given
Earnings = $10 per lawn
Required
Complete the table
Let y be the earnings for x number of lawns
Since he earns $10 per x lawns, then the expression is:
To complete the table, we have the following:
When x = 1
When x = 2
When x = 3
When x = 5
So, the complete table is:
Lawns ---Earnings
1 ----------------- 10
2 ----------------- 20
3 ----------------- 30
5 ----------------- 50
Answer:
5 significant figures
Step-by-step explanation:
Any first number than starts with > 0, it is counted as significant figures and with 0 in the middle of number, also will be counted. But if the first number is 0, you have to skip to the next number.
e.g
0.0567 = 3s.f
1.542 = 4s.f
0.0000012 = 2s.f
1200586 = 7s.f
87000000002 = 11s.f
Answer:
4(3n + 2)
Step-by-step explanation:
as we know perimeter of a square is 4 x side
one side is 3n + 2
4 sides = 4(3n +2)
First calculate the price of one pound of apples
24/5
= $4.80
Then multiply it by 6
6 x 4.80
Your price is $28.80
Answer:
A .cos(x)<1
Step-by-step explanation:
According to the first inequality
cos(x)<1
x < arccos 1
x<0
This therefore does not have a solution within the range 0 ≤ x ≤ 2pi
x cannot be leas than 0. According to the range not value, 0≤x which is equivalent to x≥0. Thus means otvis either x = 0 or x> 0.
For the second option
.cos(x/2)<1
x/2< arccos1
x/2<0
x<0
This inequality also has solution within the range 0 ≤ x ≤ 2pi since 0 falls within the range of values.
For the inequality csc(x)<1
1/sin(x) < 1
1< sin(x)
sinx>1
x>arcsin1
x>90°
x>π/2
This inequality also has solution within the range 0 ≤ x ≤ 2pi since π/2 falls within the range of values
For the inequality csc(x/2)<1
1/sin(x/2) < 1
1< sin(x/2)
sin(x/2)> 1
x/2 > arcsin1
X/2 > 90°
x>180°
x>π
This value of x also has a solution within the range.
Therefore option A is the only inequality that does not have a solution with the range.
