The level of a lake was 8 inches below normal. It decrease 1 1/4 inches in June and 2 3/8 inches more in July. What was the new
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Using the normal distribution, it is found that the probability is 0.16.
<h3>Normal Probability Distribution</h3>In a normal distribution with mean and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem, the mean and the standard deviation are given by, respectively, .
The proportion of students between 45 and 67 inches is the p-value of Z when <u>X = 67 subtracted by the p-value of Z when X = 45</u>, hence:
X = 67:
Z = -1
Z = -1 has a p-value of 0.16.
X = 45:
Z = -8.3
Z = -8.3 has a p-value of 0.
0.16 - 0 = 0.16
The probability is 0.16.
More can be learned about the normal distribution at brainly.com/question/24663213
Lets get started :)
The First question:
Diameter = 20 ft
Radius =
of 20 (diameter) = 20 ft
Area formula of a circle is
A =
r²
=(10)²
=100 ft²
≈ 314 ft²
The answer will be the second option
The Second question:
radius of circle = 12mm divided into 20 sectors area
A =r²
=(12)²
= 144 ft²
Divide into 20 equal sector areas =
≈ 22.6 mm²
Your answer will be the third option
The Third Question:
90°, sector area = 36 , Radius = ?
and cancels out
We can now cross multiply
360 × 36 = 90r²
12960 = 90r²
Divide by 90 on either side
144 = r²
Take squareroot
x = 12 in
Your answer will be the third option
The First question:
Diameter = 20 ft
Radius =
Area formula of a circle is
A =
=
=100
≈ 314 ft²
The answer will be the second option
The Second question:
radius of circle = 12mm divided into 20 sectors area
A =
=
= 144
Divide into 20 equal sector areas =
≈ 22.6 mm²
Your answer will be the third option
The Third Question:
90°, sector area = 36
We can now cross multiply
360 × 36 = 90r²
12960 = 90r²
Divide by 90 on either side
144 = r²
Take squareroot
x = 12 in
Your answer will be the third option