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zlopas [31]
3 years ago
7

Select the property that allows the left member of the equation to be changed to the right member. 8 + 0 = 8

Mathematics
1 answer:
lesya692 [45]3 years ago
7 0
<span>identity property of addition</span>
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6 0
3 years ago
A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30 What score is necessary to reach
nlexa [21]

Answer:

A score of 150.25 is necessary to reach the 75th percentile.

Step-by-step explanation:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30.

This means that \mu = 130, \sigma = 30

What score is necessary to reach the 75th percentile?

This is X when Z has a pvalue of 0.75, so X when Z = 0.675.

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 130}{30}

X - 130 = 0.675*30

X = 150.25

A score of 150.25 is necessary to reach the 75th percentile.

7 0
3 years ago
17.83 rounded to the nearest tenth
garri49 [273]
The answer would be 17.8  hope this help you

4 0
3 years ago
(a) Approximate the decimal equivalent of each number to the nearest tenth.
storchak [24]

Answer:

2,3    3    5

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Why are u ugly sbadjBCBJXZBDFChd Sb çƒ√siub cvsxdhjb fsb zf jb
allochka39001 [22]

Answer:

आपको अपने पापों के लिए पश्चाताप करना चाहिए । वे तुम्हें नष्ट कर देंगे । आप कोई मौका नहीं खड़े हैं । तुम उसके हाथ पर मर जाओगे । पछताना

Step-by-step explanation:

its just so simple! :D

6 0
3 years ago
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