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3 years ago

8

What is the polynomial 8x^2 +2x-3 in factored form

1 answer:

STALIN [3.7K]3 years ago

3 0

Experiment

(8x-3)(x+1), middle term is 5x, nope
(8x+3)(x-1), middle term is -5x, nope
(8x-1)(x+3), middle term is 23x, nope
(8x+1)(x-3), middle term is -23x,nope
(2x-3)(4x+1), middle term is -10x,nope
(2x+3)(4x-1), middle term is 10x, nope
(2x+1)(4x-3). milddle term is -2x, nope
(2x-1)(4x+3), middle term is 2x, YES

(2x-1)(4x+3)

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Step-by-step explanation:

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Answer:

$y = -\frac{3}{2}x+15$

Step-by-step explanation:

Given:

Given point P(6, 6)

The equation of the line.

$y = \frac{2}{3}x$

We need to find the equation of the line perpendicular to the given line that contains P

Solution:

The equation of the line.

$y = \frac{2}{3}x$

Now, we compare the given equation by standard form $y = mx +c$

So, slope of the line $m_{1} = \frac{2}{3}$ , and

y-intercept $c=0$

We know that the slope of the perpendicular line $m_{1}\times m_{2} = -1$

$m_{2}=-\frac{1}{m_{1}}$

$m_{2}=-\frac{1}{\frac{2}{3} }$

$m_{2}=-\frac{3}{2}$

So, the slope of the perpendicular line $m_{2}=-\frac{3}{2}$

From the above statement, line passes through the point P(6, 6).

Using slope intercept formula to know y-intercept.

$y=mx+c$

Substitute point $P(x_{1}, y_{1})=P(6, 6)$ and $m = m_{2}=-\frac{3}{2}$

$6=-\frac{3}{2}\times 6 +c$

$6=-3\times 3 +c$

$c=6+9$

$c=15$

So, the y-intercept of the perpendicular line $c=15$

Using point slope formula.

$y=mx+c$

Substitute $m = m_{2}=-\frac{3}{2}$ and $c=15$ in above equation.

$y = -\frac{3}{2}x+15$

Therefore: the equation of the perpendicular line $y = -\frac{3}{2}x+15$

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Please answer quickly Ill give brainliest.

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Step-by-step explanation:

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