The zeros for this function are -2, -1 and a double root of 0.
You can find this by first factoring the polynomial on the inside of the parenthesis. Polynomials like this can be factored by looking for two numbers that multiply to the constant (2) and add up to the second coefficient (3). The numbers 2 and 1 satisfy both of those needs and thus can be used as the numbers in a factoring.
x^2(x^2 + 3x + 2)
x^2(x + 2)(x + 1)
Now to find the zeros, we set each part equal to 0. You may want to split the x^2 into two separate x's for this purpose.
(x)(x)(x + 2)(x + 1)
x = 0
x = 0
x + 2 = 0
x = -2
x + 1 = 0
x = -1
-3x + 2y = -3
4x - y = -1
2(4x - y = -1)
-3x +2y = -3
8x -2y = -2
-5x = -5
/-5
X = 1
Answer:
$14.45
Step-by-step explanation:
Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)
Answer:
A) Real Roots
B) Imaginary Roots
C) Equal Roots
D) Unequal Roots
E) Rational Roots
F) Irrational Roots
Step-by-step explanation:
The equation with one variable , in which the highest power of variable is two , is know as QUADRATIC EQUATION
ex - 3x² + 4x + 7 = 0
Every quadratic equation gives to values of unknown variables and these values is called roots of equation .
The quadratic equation have three roots :
A) Real Roots
B) Imaginary Roots
C) Equal Roots
D) Unequal Roots
E) Rational Roots
F) Irrational Roots
The nature of Roots depends entirely on the value of it Discriminant
If D = 0 , Roots are real and equal
If D 
, roots are real and unequal
If D 
,roots are imaginary
where D = b² - 4ac for any quadratic equation ax² + bx + c = 0
Answer
