Answer:
3
x
y
2
Step-by-step explanation:
Answer:
20
Step-by-step explanation:
For the sake of the problem, let's make female workers "x" and male workers "y".
x+y<40 This equation shows that the total number of workers has a max of 40.
30x+20y<1,000 This equation shows that the total cost the manager pays ($30 to each woman, $20 to each man) has a max of $1,000.
Now you can solve for x and y.
X+y<40
-y -y
X<-y+40
Substitute -y+40 in for X in the second equation
30(-y+40)+20y<1,000
-30y+1200+20y<1,000 Distribute
-10y+1,200<1,000 Combine like terms
-10y<-200 Subtract 1,200
y>20 Divide by -10; flip the sign
Since y>20, and y=male workers, you now know that the minimum
number of male workers he should send is 20
Corresponding angles- a, d, h, l and s
Alternate interior- c, f, i, o, and t
Same side interior- e, g, k, m, and p
Alternate exterior- n, q, r
• for j and b I’m not sure
The Answer Would Be 64 because if you divide 8/4.5 its equal to 64/36.
Answer:
So, the first three nonzero terms in the Maclaurin series are:
Step-by-step explanation:
From exercise we have the next function y = 6 sec(3x).
We know that Maclaurin series for the function sec x, have the following form:
So, for the given function y = 6 sec(3x), we get:
So, the first three nonzero terms in the Maclaurin series are:
