Quarters = x
dimes = 196 - x
10(196 - x) + 25x = 3940
1960 - 10x +25x = 3940
1960 + 15x = 3940
15x = 1980
x = 132
169 - 132 = 64
Therefor there are 132 quarters and 64 dimes
Given:
A number when divided by 780 gives remainder 38.
To find:
The reminder that would be obtained by dividing same number by 26.
Solution:
According to Euclis' division algorithm,
...(i)
Where, q is quotient and 
is the remainder.
It is given that a number when divided by 780 gives remainder 38.
Substituting 
in (i), we get
So, given number is in the form of 
, where q is an integer.
On dividing by 26, we get
Since q is an integer, therefore (30q+1) is also an integer but 
is not an integer. Here 26 is divisor and 12 is remainder.
Therefore, the required remainder is 12.
Answer:
1. 3
2. 2
Step-by-step explanation:
| |
x | + | 1 | | x^2 | + | 4 x | - | 2
x^3 | + | 5 x^2 | + | 2 x | + | 1
x^3 | + | x^2 | | | |
| | 4 x^2 | + | 2 x | |
| | 4 x^2 | + | 4 x | |
| | | | -2 x | + | 1
| | | | -2 x | - | 2
| | | | | | 3
__________________________________________
| |
x | - | 5 | | x^2 | - | x | + | 0
x^3 | - | 6 x^2 | + | 5 x | + | 2
x^3 | - | 5 x^2 | | | |
| | -x^2 | + | 5 x | |
| | -x^2 | + | 5 x | |
| | | | | | 2
| | | | | | 0
| | | | | | 2
Answer:
No
Step-by-step explanation:
