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Len [333]
3 years ago
5

Solve the inequality

Mathematics
2 answers:
irina1246 [14]3 years ago
7 0

Answer:

D

Step-by-step explanation:

x/4≥-6

 *4  *4

x≥-24

So it's D.

---

hope it helps

const2013 [10]3 years ago
4 0

\huge\text{Hey there!}

\mathsf{\dfrac{x}{4}\geq-6}

\large\text{SUBSITUTE 1 where x is at temporarily, so we can simplify both}\\\large\text{sides of your inequality}

\large\text{NEW EQUATION: }\mathsf{\dfrac{1}{4}x \geq-6}

\large\text{MULTIPLY by 6 to BOTH SIDES}

\mathsf{4\times\dfrac{}{}x \geq 4\times-6}

\large\text{CANCEL out: }\mathsf{4\times\dfrac{1}{4}}\large\text{ because that gives you the value of 1}

\large\text{KEEP: }\mathsf{4\times-6}\large\text{ because it helps you find out the number or value}\\\large\text{that is being compared to your x-value}

\mathsf{4\times-6=\boxed{\bf -24}}

\large\text{So, the number \underline{-24} is being compared to your x-value}

\bullet\large\text{ Your circle is CLOSED and it is shaded to the right side of the}\\\large\text{number}\huge\checkmark\\\\\\\large\textsf{Random fact about the inequality}\uparrow

\boxed{\boxed{\large\text{Answer: \bf x}\bf \geq\large\textsf{\bf -24 \huge\text{Option D.}}}}\huge\checkmark

\large\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

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Determine if the lines r1(t) = <3, 0, 2> + t <1, 2, −2> and r2(s) = <0, 1, −1> + s <4, 1, 1> intersect,
Temka [501]

Answer:

Yes lines are intersecting, point of intersection is <4,2,0>.

Step-by-step explanation:

Given parametric equations of line are:

r_{1}(t) =  + t  \\ r_{1}(t) = \\ r_{1}(t) = ---(1)

r_{2}(s) =  + s \\ r_{2}(s) = \\ r_{2}(s) = ---(2)\\

If lines are intersecting then parametric coordinates of (1) are equal to (2)

3+t=4s---(A)\\2t=1+s---(B)\\2-2t=s-1---(C)\\

Considering A and B to find values of t and s

From A

t=4s-3---(D)

Putting in (B)

2(4s-3)=1+s

8s-6=1+s

7s=7

s=1

Then

t=4-3

t=1

If lines are intersecting then these values of s and t must satisfy (C)

2-2(1)=1-1

0=0

This shows lines are intersecting.

At this value of t, (1) becomes

r_{1}(1) = \\=

Putting s=1 in (2)

r_{2}(1)=4, 1+1,-1+1>\\=

Point of intersection is <4,2,0>.

4 0
3 years ago
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