Answer:
The numerical limits for a B grade is between 81 and 89.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

B: Scores below the top 13% and above the bottom 56%
Below the top 13%:
Below the 100-13 = 87th percentile. So below the value of X when Z has a pvalue of 0.87. So below X when Z = 1.127. So




Above the bottom 56:
Above the 56th percentile, so above the value of X when Z has a pvalue of 0.56. So above X when Z = 0.15. So




The numerical limits for a B grade is between 81 and 89.
Image is missing, so i have attached it.
Answer:
AC = 10sin 40°
Step-by-step explanation:
From the diagram attached, using terms in trigonometric ratio, AC is the opposite side, BC is the adjacent side and AB is the hypotenuse.
Thus, since we want to find AC;
We know that in trigonometric ratios; opposite/hypotenuse = sin θ
In the diagram, θ = 40° and AB = 10
Thus,
AC/10 = sin 40°
Multiply both sides by 10 to get;
AC = 10sin 40°
Surface Area of can (SA) = (2 · π · r²) + (2 · π · r · h)
296.73 = [2 · π · (4.5)²] + [2 · π · (4.5) · h]
296.73 = 40.5π + 9π · h
296.73 - 40.5π = 9π · h
(296.73 - 40.5π)/9π = h
169.5/28.27 = h
6 = h
Answer: 6 inches
Answer:
24780
Step-by-step explanation:
might not be right but 24780 because 23600*5% is 1180 and add that to the original 23600 to get 24780
He is false the equation should be as follows