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Papessa [141]
3 years ago
10

A spring-loaded dart gun is used to shoot a dart straight up into the air, and the dart reaches a maximum height of 24 meters ab

ove its point of release. The same dart is shot up a second time from the same gun, but this time the spring is compressed only half as far (compared to the first shot). How far up does the dart go this time? (Neglect friction and assume the spring is ideal and massless.)
Physics
1 answer:
Vinil7 [7]3 years ago
4 0

Answer:the dart goes 6m deep

Explanation:

1/2 k x1² = mgh1 (1)

1/2 k x2² = mgh2 (2)

Dividing 1 by 2 gives the relation

(x1/x2)²= h1/h2

using given

[x/ (x/2)]²=24/h2

4= 24/h2

h2=6 m

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Please please please please help soon!!
vodomira [7]
Your answer is C m8

hope i helped

4 0
3 years ago
A pendulum of length 130.0 cm has a period of oscillation, T₁. The bob is pulled and released to move in a horizontal circle of
Anastasy [175]

The ratio of T1 : T2 is 1.6

<h3>What is Simple Harmonic Motion ?</h3>

SHM is the periodic motion of a particle along a line such that the acceleration of the body is directed toward a fixed point and proportional to its displacement.

Given that a pendulum of length 130.0 cm has a period of oscillation, T₁.

Then, The period T₁ = 2\pi\sqrt{\frac{l}{g} }

T₁ = 2 x 3.142 \sqrt{\frac{1.3}{10} }

T₁ = 6.284 x 0.36

T₁ = 2.266

But if T = 0

then, mv^{2} /r = mg

the m will cancel out

Then v = \sqrt{rg}

where r = 50/100 = 0.5m

Substitute into the formula

v = \sqrt{ 0.5 * 10}

v = 2.24 m/s

Also, given that the bob is pulled and released to move in a horizontal circle of radius 50.0 cm and the period of rotation is T2,

w = 2\pif

w = 2\pi/T

but v = wr

w = v/r

Therefore,

v/r = 2\pi/T

Substitute all the parameters into the formula

2.24/0.5 = (2 x 3.1423) /T

T = 6.284/4.472

T = 1.405 = T_{2}

The ratio T₁: T2 will be 2.266/1.405

The ratio is 1.6

Learn more about Simple Harmonic Motion here: brainly.com/question/24646514

#SPJ1

4 0
2 years ago
Which statement best compares the accelerations of two objects in free fall?
gregori [183]

Answer:

D) The objects have the same acceleration. With no air resistance and the same gravity, the acceleration due to gravity should be the same for both objects.

8 0
3 years ago
1 oto đang có v = 54km /h thì hãm phanh . cđ chậm dần đều đi đc 50m nữa thì dừng lại xác định gia tốc , vận tốc oto sau 2 giây k
madam [21]

Answer:

huh?

Explanation:

I'm so sorry but, i don't get it

3 0
3 years ago
A 0.86 kg rock is projected from the edge of the top of a building with an initial velocity of 8.65 m/s at an angle 46◦ above th
Georgia [21]

Answer:

Height of the building = 11.4 m

Explanation:

As we know that the stone is projected at an angle 46 degree with speed 8.65 m/s

so the two components of the speed is given as

v_x = 8.65 cos46

v_x = 6 m/s

vertical component of the speed is given as

v_y = 8.65 sin46

v_y = 6.22 m/s

now we know that the ball strike at horizontal distance of 13.7 m

so we will have

x = v_x t

13.7 = 6 t

t = 2.28 s

now we know that in vertical direction ball will move under uniform gravity so we can use kinematics

y = v_y t + \frac{1}{2}at^2

y = 6.22(2.28) - \frac{1}{2}(9.81)(2.28^2)

y = -11.4 m

Height of the building = 11.4 m

3 0
3 years ago
Read 2 more answers
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