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Answer:
x=0.154kg
Explanation:
(x*L)+(0.5kg*4200*50)+(x*4200*(-50)=0
(x*333 000J/kg*c)+(0.5kg*4200J/kg*C*(-40C))+(x*4200J/kg*C*50C)=0
Answer:
- The size of a force
- The perpendicular distance from the pivot the line of action of force
Explanation:
Factors that affect the moment of a force are;
- The size of a force
- The perpendicular distance from the pivot the line of action of force
The magnitude of force applied is directly proportional to the moment of force in that for a perpendicular distance d, increased in force applied will result to a higher moment of force. When the perpendicular distance from the pivot is decreased while the force applied remains constant, the moment of force decreases.
Answer: Magnitude of electric field =p × Ke × Q/d^3
Explanation: Using Coulombs law of point charge,each charge on the circle would exert a fieldEc at point given by:
Ec= Ke × (Q/n)/d^2
Where Ke= Coulomb's constant
d= distance between the charges and the point of measurement, P with d^2=a^2+p^2
(Q/n)= Magnitude of the charge.
For charges in a circle,all the force components and direction(x,z) are cancelled by the symmetry,leaving only the vertical force(y-direction)
The Resultant vector will be
Ecy=Eq × sin(theta)
Ecy=Ke × (Q/n)/d^2 ×(p/d)
Adding the forces from all the charges,the magnitude of electric field Ey=n×Ecy
/Ey/= n ×[Ke ×(Q/n)/d^2 ×(p/d)]
/Ey/= p × Ke × (Q/d^3)
Answer:
1.65 m
Explanation:
Energy from spring, 
is given by
where k is spring constant and x is the compression distance
Kinetic energy, KE at the highest point is given by
where m is mass and v is velocity
KE=0.5*0.0227*2.27= 0.058485 J
Potential energy, PE of spring is given by
PE=mgh where g is gravitational constant and h is maximum height reached by the mouse
PE=0.0227*9.81= 0.222687h
According to the principle of conservation of energy, the potential energy of the compressed spring is equal to the potential and kinetic energy of the mouse at the maximum high point.
0.425=0.222687h+0.058485
h=(0.425-0.058485)/ 0.222687=1.646671 m
h=1.65 m
