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Studentka2010 [4]

3 years ago

6

A 10kg roller coaster does a loop-de-loop and it’s your job to make sure it is safe. The people will fall out if the cart’s spee

d is less than 40m/s when it goes upside down. How high up does the car have to be at point A to make it? Fill in everything else as well.
Location

PE

KE

TE

A

h =

v = 0m/s

B

h = 0m

v =

C

h = 15m

PE=m*g*h

v = 40m/s

KE=0.5*m*v2=

TE=PE+KE

D

h = 0m

v =

E

h = 10m

v =

F

h = 20m

v =

1 answer:

Bingel [31]3 years ago

6 0

Answer:

3

Explanation:

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A ball is launched from the ground with a horizontal speed of 30 m/s and a vertical speed of 30 m/s. What will the horizontal sp

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1. What is the name given to the total possibility of sound frequencies

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Explanation:

1. The entire span of possible sound waves is called the acoustic spectrum. It is subdivided into infrasonic sounds, audible sounds, and ultrasonic sounds.

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In a lab experiment a light flexible string is wrapped around a solid cylinder with mass M = 9.50 kg and radius R. The cylinder

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Answer: $3.79 m/s^2$

Explanation:

Given

Mass $M=9.5 kg$

$m=3 kg$

Net Force is equivalent to $\sum F=ma$

with tension T in the string

For mass $m$

$mg-T=ma$

$T=mg-ma--------1$

For cylinder

$T\cdot R=I\times \alpha$

I for solid cylinder is $\frac{2}{5}MR^2 , and \alpha =\frac{a}{R}$

thus $T=\frac{Ma}{2}----2$

Substitute the value of T we get

$\frac{Ma}{2}=mg-ma$

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3 years ago

A helicopter lifts a 72 kg astronaut 15 m vertically from the ocean by means of a cable. The acceleration of the astronaut is g/

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Answer:

a) $F_H=776.952\ N$

b) $F_g=706.32\ N$

c) $v=5.4249\ m.s^{-1}$

d) $KE=1059.48\ J$

Explanation:

Given:

mass of the astronaut, $m=72\ kg$

vertical displacement of the astronaut, $h=15\ m$

acceleration of the astronaut while the lift, $a=\frac{g}{10} =0.981\ m.s^{-2}$

a)

<u>Now the force of lift by the helicopter:</u>

Here the lift force is the resultant of the force of gravity being overcome by the force of helicopter.

$F_H-F_g=m.a$

where:

$F_H=$ force by the helicopter

$F_g=$ force of gravity

$F_H=72\times 0.981+72\times9.81$

$F_H=776.952\ N$

b)

The gravitational force on the astronaut:

$F_g=m.g$

$F_g=72\times 9.81$

$F_g=706.32\ N$

d)

Since the astronaut has been picked from an ocean we assume her initial velocity to be zero, $u=0\ m.s^{-1}$

using equation of motion:

$v^2=u^2+2a.h$

$v^2=0^2+2\times 0.981\times 15$

$v=5.4249\ m.s^{-1}$

c)

Hence the kinetic energy:

$KE=\frac{1}{2} m.v^2$

$KE=0.5\times 72\times 5.4249^2$

$KE=1059.48\ J$

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