<span>A full moon is at its brightest, and here is no disk to be seen. New moons are barely visable.</span>
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-Try one new workout every month. Keeping the same exact routine when it comes to your fitness is never a good thing.
-More water
With any diet, the most important thing to remember is to stay hydrated. Drinking water will support your body with digestion, transporting nutrients to your bones and muscles, and even improving cognitive function.
Ideally, you want to drink about half your body weight in ounces per day, i.e. if you weight 150 pounds, you should drink 75 ounces of water a day.
-Stretching
The benefits are vast and the repercussions of failing to stretch can be dramatic.
Do yourself a favor and always stretch before and after a workout. This will promote a healthy cool down, improve flexibility, and reduce next day aches. Failure to stretch can lead to injures and muscle damage.
-Body Fat
This may seem like an obvious one, but it is one of the most important steps to a healthier you. Reducing your body fat has a lot of benefits such as:
Improved joints and tendons
Lowered risk of diabetes
Reduced risk of heart disease
Reduced inflammation
Better performance and endurance
Improved appearance and confidence
Better hormonal profiles in your body
Remember, it is not a race to see how quickly you can decrease your body fat. Healthy weight loss is around 1-2 pounds a week for your fitness goals.[2]
Crash dieting or pushing yourself too much in the gym can lead to you achieving an unrealistic target, and you may find yourself gaining all the weight you have lost.
Think of it as a lifestyle, and take it slow and steady.
The net force is the vector
∑ F = (450 N) (cos(42°) i + sin(42°) j)
and two of the forces provided by the girls are
F₁ = (310 N) (cos(115°) i + sin(115°) j)
F₂ = (250 N) (cos(285°) i + sin(285°) j)
Then the force provided by the third girl is the vector
F₃ = ∑ F - F₁ - F₂
F₃ = ((450 N) cos(42°) - (310 N) cos(115°) - (250 N) cos(285°)) i
… … … + ((450 N) sin(42°) - (310 N) sin(115°) - (250 N) sin(285°)) j
F₃ ≈ (400.722 N) i + (261.635 N) j
So, the third girl provided a force of magnitude
||F₃|| = √((400.722 N)² + (261.635 N)²) ≈ 478.572 N ≈ 480 N
pointing in a direction
arctan((261.635 N)/(400.722 N)) ≈ 33.1409° ≈ 33°
relative to East which refers to 0°; that is, 33° N of E or E33°N. Since the other forces are given relative to North or South, we can write this direction as N57°E.
So, the third girl pushed with force 480 N [N57°E].
