1. EDBAC because C is the youngest and goes through all of the other older ones
<span>In codominance, two dominant alleles are expressed at the same time? Yes! Indeed they do this is totally true! :)</span>
Answer:
When two people create the next generation if the trait is dominant and possessed by one it will commonly be passed down if it is passive then it is a bit less likely to be passe down unless both parents share the trait as 50% of genetic traits come from both sides.
Explanation:
<span>Benedicts test is used for testing reducing sugar in urine and food samples. Biuret test is used for testing proteins in a sample. Sudar Red test is used to detect lipids in a sample. For starch The Lugol test is carried out. when Lugols iodine is added to sample to the powder it will turn deep bluish black color showing the sample contain starch. The other tests will not give positive results with starch powder.</span>
The answer is 0.47 or 47%.
Let's first distinguish some terms and their frequencies.
R - the dominant allele that causes red eyes
r - the recessive allele that causes green eyes
Since R is dominant over r, lizards with at least one dominant R allele will have red eyes. Therefore, the genotypes and the phenotypes are as following:
genotypes - phenotypes
RR - the lizards with red eyes
Rr - the lizards with red eyes
rr - the lizards with green eyes
Now, we will use some Hardy-Weinberg equations:
p + q = 1
p² + 2pq + q² = 1
where:
p - the frequency of dominant allele R
q - the frequency of recessive allele r
p² - the frequency of lizards with genotype RR
2pq - the frequency of lizards with genotype Rr
q² - the frequency of lizards with genotype <span>rr
</span>
We are interested in <span>the frequency p of the dominant R allele.
</span>So, we have the frequency (72%) of the lizards that have red eyes. However, lizards with genotypes RR and Rr will have red eyes. Since their frequencies are p² and 2pq, respectively, we have:
p² and 2pq = 72% = 72/100 = 0.72
Now, use this in the equation p² + 2pq + q² = 1:
0.72 + q² = 1
q² = 1 - 0.72 = 0.28
From here, we will calculate q and later p using the formula p + q = 1:
q² = 0.28
q = √0.28 = 0.53
p + q = 1
p + 0.53 = 1
p = 1 - 0.53
p = 0.47