P = 2(L + W)
P = 80
W = 1/3L
80 = 2(L + 1/3L)
80 = 2(3/3L + 1/3L)
80 = 2(4/3L)
80 = 8/3L
80 * 3/8 = L
240/8 = L
30 = L .... length (L) is 30 ft
W = 1/3L
W = 1/3(30)
W = 30/3
W = 10 <== width (W) = 10 ft
Answer:
Domain: (−∞,∞),{x|x∈R}
Range: (−∞,∞),{y|y∈R}
Step-by-step explanation:
Find the domain by finding where the function is defined. The range is the set of values that correspond with the domain.
Domain: (−∞,∞),{x|x∈R}
Range: (−∞,∞),{y|y∈R}
Answer:
<h2 /><h2>The interquartile range (IQR) is the difference between the upper (Q3) and lower (Q1) quartiles, and describes the middle 50% of values when ordered from lowest to highest. The IQR is often seen as a better measure of spread than the range as it is not affected by outliers. Interquartile Range. 25% of values.</h2>
<h2 />
<h2>here your answer </h2>
Answer: B
Step-by-step explanation:
If ZM is an obtuse angle (greater than 90), then ZM and ZP will not add up to 90.
If ZP is 120, then ZM and ZP will not add up to 90.
There are multiple contradicting statements within this problem, as noted above.
Hope this helps!
