Divide: 8.4 x 10^12<br> --------------<br> 4.2 x 10^6

A salesperson obtained a systematic sample of size 30 from a list of 750 clients. To do so, he randomly selected a number from 1

n200080 [17]

Answer:

B. 17,42, ..., 742

Step-by-step explanation:

In the systematic sampling after choosing the first entry every kth entry is selected according to given procedure

starting entry, starting entry+k, starting entry+2k,..., starting entry+(n-1)k.

Where n denotes the sample size.

we are given that starting entry is 17, sample size is 30 and k=25.

Then the number corresponds to selected clients are

17, 17+25, ..., 17+(30-1)25

17, 42, ..., 742

8 0

3 years ago

Figure A is a scale image of figure B

serious [3.7K]

X=36

Divide the corresponding side (16) by 4/7

5 0

3 years ago

Josh had $10 more than Carly, so he gave Carly half of his money. Then Carly had more money than josh, so she gave Josh $4. Then

DedPeter [7]

each person starts with $8.

<u>Step-by-step explanation:</u>

Here we have , Josh had $10 more than Carly, so he gave Carly half of his money. Then Carly had more money than josh, so she gave Josh $4. Then they both had $13. We need to find How much money did each person start . Let's find out:

Suppose Carly had $x , Josh had $10 more than Carly i.e. $(x+10), so he gave Carly half of his money i.e.

⇒ $\frac{x+10}{2}$ ,Now , Josh have $ $\frac{x+10}{2}$ & Carly have $x + \frac{x+10}{2}$ .

Then Carly had more money than josh, so she gave Josh $4 . So ,

Josh now have $ $(4+\frac{x+10}{2})$ and Carly now have $ $(x+\frac{x+10}{2} -4)$ . Since both are equal :

⇒ $(x+\frac{x+10}{2} -4) = (4+\frac{x+10}{2})$

⇒ $x-4 = 4$

⇒ $x=8$

Therefore , each person starts with $8.

8 0

3 years ago

Samuel tiene 11 cajas con mosaico cuadrado de 20 cm por lado y quiere cubrir una pared que mide 3 cm y de largo 2 cm de alto.Si

kirza4 [7]

Answer: Samuel no necesita comprar mas cajas.

Step-by-step explanation:

Cada mosaico es un cuadrado de 20cm por lado.

Entonces el área de cada mosaico es:

A = 20cm*20cm = 400cm^2.

En una caja hay 14 mosaicos, entonces cada caja puede cubrir:

14*400cm^2 = 5,600cm^2.

Ahora, el problema dice que la pared mide 3cm por 2 cm.

En ese caso, con un solo mosaico cubrirías la pared, entonces supongo que esta mal escrito.

Las dimensiones de la pared serian 3 metros por 2 metros.

1 m = 100cm

Entonces la pared es 300cm por 200cm.

El área total de la pared seria:

300cm*200cm = 60,000cm^2.

Ahora, cada caja de mosaicos cubre 5,600 cm^2.

Entonces el numero de cajas necesarias para cubrir toda la pared es:

(60,000cm^2)/(5,600cm^2) = 10.7

Entonces se necesitan 10.7 cajas para cubrir esa pared, y Samuel tiene 11, entonces el no necesita comprar mas cajas.

4 0

3 years ago

What is the solution to the system of equations?

Llana [10]

Solution in attachment.

3 0

3 years ago

Divide: 8.4 x 10^12 -------------- 4.2 x 10^6