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3 years ago

Triangle ABC is transformed to create triangle MNO and triangle PQR as described below

Mathematics

1 answer:

goldenfox [79]3 years ago

5 0

Answer:

The correct answer is the second option

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Heeelp!!

stich3 [128]

Answer:

x3=y

Step-by-step explanation:

7 0

3 years ago

"If < A and then m< A + m/B = 90°"<br> A. Complement Theorem<br> B. Definition of a Right Angle<br> C. Congruent Complemen

9966 [12]

If < A and then m< A + m/B = 90°, then D. Definition of Complementary Angles

<h3>What is a complementary angle?</h3>

When the sum of two angles is 90°, the angles are said to be complementary. In other words, if two angles add up to form a right angle, they are called complementary angles. The two angles are said to complement each other in this context.

Supplementary angles are two angles that add up to 180 degrees, whereas complementary angles are two angles that add up to 90 degrees.

An angle measuring 72 degrees has a complement of 18 degrees.

Therefore, based on the information given, the correct option is D.

Learn more about complementary angles on:

brainly.com/question/16281260

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8 0

1 year ago

Find the area of a rectangle with a length of 5 1/3 inches and a width of 2/3 inch

neonofarm [45]

Step-by-step explanation:

$length \: of \: rectangle \\ l = 5 \frac{1}{3} \: inches = \frac{16}{3} \:inches \\ \\ width \: of \: rectangle \: \\ w = \frac{2}{3} \: inch \\ \\ area \: of \: rectangle \\ = l \times w \\ \\ = \frac{16}{3} \times \frac{2}{3} \\ \\ = \frac{32}{9} \\ \\ \red{ \boxed{ \therefore area \: of \: rectangle = 3 \frac{5}{9} \: {inch}^{2} }}$

4 0

3 years ago

A 2-yard piece of ribbon costs $32.04. What is the price per foot?

Sidana [21]

Answer:

$5.34 per food

Step-by-step explanation: There are 6 feet in 2 yards.

I take 32.04 and divide it by 6 because there are 6 feet.

3 0

3 years ago

The answer to these please!

igomit [66]

$\sqrt[4]{(4a^{2})^{6}} = \sqrt[4]{4096a^{12}} = 8a^{3}$

$\sqrt[7]{(b^{\frac{5}{3}})^{8}} = \sqrt[7]{b^\frac{40}{3}} = b^{\frac{40}{21}} = \sqrt[21]{b^{40}} = \sqrt[21]{b^{21} * b^{19}} = \sqrt[21]{b^{21}} \sqrt[21]{b^{19}} = b\sqrt[21]{b^{19}}$

$\sqrt[3]{\frac{c^{9}}{c^{3}}} = \sqrt[3]{c^{6}} = c^{2}$

$\sqrt[3]{27d^{6} * 8d^{-4}} = \sqrt[3]{27d^{6} * \frac{8}{d^{4}}} = \sqrt[3]{216d^{2}} = 6\sqrt[3]{d^{2}} = 6d^{\frac{2}{3}}$

4 0

3 years ago

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