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maksim [4K]
3 years ago
15

Which choice is a correct congruence statement for the triangles?

Mathematics
1 answer:
denpristay [2]3 years ago
4 0
<h3>Answer: Choice 3)  Triangle ACB = Triangle CAD</h3>

The reason why is because the order is important when it comes to congruent statements. I'm referring to the order of the letters of ACB and CAD.

Each answer choice has "ACB" in that exact order shown on the left hand side of each congruent statement. We have "A" listed first, then "C" next. In short, segment AC is the first thing mentioned of ACB. This means that we need to list out segment AC as the first thing for the other triangle as well, in order to have a match. Segment AC is the same as segment CA, which is the first segment mentioned in triangle CAD. That's why choice 3 is the answer.

Note how something like triangle CDA won't work since segment CD is listed first, which doesn't pair up with segment AC. This allows us to rule out the first answer choice. Choices 2 and 4 can be eliminated for similar reasons.

Put another way: let's assume choice 1 was the answer. That would mean that AC = CD as they are the first pair of letters of ACB and CDA respectively. But the diagram shows that AC = CD is not true; otherwise, the segments would have similar tickmarks to show they are the same length. This is an alternative way to see why choices 1, 2, and 4 can be crossed off the list.

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3 years ago
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MArishka [77]

Answer:

Step-by-step explanation:

Each ticket is $15.  The number of tickets is what we are trying to solve for.  The class spends a certain amount of money to prepare for the formal.  They hope that the money they make in ticket sales is MORE than what they spend.  The expression that represents the number of tickets at $15 each is 15x, where x is the number of tickets.  They hope that the sales are greater than what they spend, so what we have so far is

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15x > 600...

but they also have to print a certain, unknown number of tickets at .50 each.  The expression that represents the printing of each ticket is .5x (we can drop the 0; it doesn't change the answer or make it wrong if we drop it off).  So the cost for this affair is the food + the printing.

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Solve this inequality for x.  Begin by subtracting .5 from both sides to get

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Because we are not selling (or printing) .3 of a ticket, it's safe to say (and also correct!) that they need to sell (and print) 41 tickets.  If they sell 41 tickets, the profit is found by

15(41) > 600 + .5(41)

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This means that at 41 tickets, they make a profit.  At 40 tickets, the inequality looks like this:

15(40) > 600 + .5(40) and

600 > 620.  This is not true, so 40 tickets isn't enough.

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