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maksim [4K]
3 years ago
15

Which choice is a correct congruence statement for the triangles?

Mathematics
1 answer:
denpristay [2]3 years ago
4 0
<h3>Answer: Choice 3)  Triangle ACB = Triangle CAD</h3>

The reason why is because the order is important when it comes to congruent statements. I'm referring to the order of the letters of ACB and CAD.

Each answer choice has "ACB" in that exact order shown on the left hand side of each congruent statement. We have "A" listed first, then "C" next. In short, segment AC is the first thing mentioned of ACB. This means that we need to list out segment AC as the first thing for the other triangle as well, in order to have a match. Segment AC is the same as segment CA, which is the first segment mentioned in triangle CAD. That's why choice 3 is the answer.

Note how something like triangle CDA won't work since segment CD is listed first, which doesn't pair up with segment AC. This allows us to rule out the first answer choice. Choices 2 and 4 can be eliminated for similar reasons.

Put another way: let's assume choice 1 was the answer. That would mean that AC = CD as they are the first pair of letters of ACB and CDA respectively. But the diagram shows that AC = CD is not true; otherwise, the segments would have similar tickmarks to show they are the same length. This is an alternative way to see why choices 1, 2, and 4 can be crossed off the list.

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The euro has depreciated and the dollar as appreciated
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4 3/4 divided by 1 1/6
ozzi

Answer:

2\frac{13}{22}

Step-by-step explanation:

=\frac{19}{4}\div \frac{11}{6}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}

=\frac{19}{4}\times \frac{6}{11}

=\frac{19}{2}\times \frac{3}{11}

\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}

=\frac{19\times \:3}{2\times \:11}

\mathrm{Multiply\:the\:numbers:}\:19\times \:3=57

=\frac{57}{2\times \:11}

\mathrm{Multiply\:the\:numbers:}\:2\times \:11=22

=\frac{57}{22}

=2\frac{13}{22}

5 0
2 years ago
Evaluate x + y when x = - 18.2 and y = 3.6
Contact [7]
-18.2 + 3.6= -14.6 is the answer to the question
3 0
3 years ago
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Adam must fly home to city A from a business meeting in city B. One flight option flies directly to city A from​ B, a distance o
g100num [7]

Answer:

The value  is  k =109.6 \ miles

Step-by-step explanation:

The diagram illustrating the question is shown on the first uploaded image

From the question we are told that

   The distance from city A to B is   AB =  467.3 miles

   The bearing from B to  C is  \theta_{BC} =  N 28.7E

   The bearing from B to  A is  \theta_{BA} =  N 60.7E

   The  bearing from A to  B is   \theta_{AB} =  S60.7W

    The  bearing from A to  C is   \theta_{AC} =  S79.1W

Generally from the diagram

     \theta_A  =  180 - 60.7 -79.1

=>  \theta_A  =  40.2 ^o

Also

     \theta_B  =  32^o

and  

      \theta_C  =  180 - (\theta_A  +\theta_B )

=>   \theta_C  =  180 - (40.2  + 32 )

=>   \theta_C  =  107.8 ^o

Generally according to Sine Rule

     \frac{BC}{sin (\theta_A)}  = \frac{CA}{sin (\theta_B)} =\frac{AB}{sin (\theta_C)}

=>   \frac{BC}{sin (40.2)}  = \frac{CA}{sin (32)} =\frac{467.3 }{sin (107.8)}    

So

     \frac{BC}{sin (40.2)}  = \frac{467.3 }{sin (107.8)}

=>  BC = 316.8 \ miles

Also  

    \frac{CA}{sin (32)} =  \frac{467.3 }{sin (107.8)}

    CA = 260 .1 \ miles

Generally the additional flyer miles that Adam will receive if he takes the connecting flight rather than the direct​ flight is mathematically represented as

      k = [CA +BC]  - AB

=>     k = [260 .1 +316.8]- 467.3

=>  k =109.6 \ miles

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Answer: 23x

Step-by-step explanation:

5 0
3 years ago
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