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Stells [14]
3 years ago
13

Meena is helping her school librarian to arrange books on the shelves. Based on this situation, answer the following questions:

(Attempt any 4 questions)
2/3 of the books are Language books and 1/5 are Science books. What can you conclude from this statement?
There are fewer Language books than Science books
There are more Language books than Science books
They are equal in number
Can’t say anything

If the remaining books are of Mathematics, what is the fraction of those books?
1/15 b) 4/15 c) 2/15 d) 7/15
Mathematics
1 answer:
Illusion [34]3 years ago
5 0

Answer:

c) 2/15

Step-by-step explanation:

LA= 2/3 = 10/15

S=1/5 = 3/15

15/15 - 13/15 = 2/15

Math books= 2/15

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Answer:

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Step-by-step explanation:

1. Let b be the number and B be the set, so mathematically, it is written as

b ∈ B.

2. Let  a be an element of natural number N and 2a be an even number. Since 2a is in the set of integers Z, we write

∀ a ∈ N; 2a ∈ Z

3. Let N represent the set of natural numbers, Z represent the set of integers, Q represent the set of rational numbers, and R represent the set of rational numbers.

Since each set is a subset of the latter set, we write

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4. Let J be the negative integer which is an element if negative integers. Let the set of negative integers be represented by Z⁻. Since J is less than or equal to its inverse, we write

J ≤ J⁻¹ : J ∈ Z⁻

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Step-by-step explanation:

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Step-by-step explanation:

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certain computer virus can damage any file with probability 35%, independently of other files. Suppose this virus enters a folde
Ksivusya [100]

Answer:

0.623 is the probability that between 800 and 850 files get damaged.

Step-by-step explanation:

We are given the following information:

We treat virus can damage computer as a success.

P( virus can damage computer) = 35% = 0.35

The conditions for normal distribution are satisfied.

By normal approximation:

\mu = np = 2400(0.35) = 840\\\sigma = \sqrt{np(1-p)} = \sqrt{2400(0.35)(1-0.35)} = $$23.36

We have to evaluate probability that between 800 and 850 files get damaged.

P(800 \leq x \leq 850) = P(\displaystyle\frac{800 - 840}{23.36} \leq z \leq \displaystyle\frac{850-840}{23.36}) = P(-1.712 \leq z \leq 0)\\\\= P(z \leq 0.428) - P(z < -1.712)\\= 0.666 - 0.043 = 0.623 = 62.3\%

P(800 \leq x \leq 850) = 62.3\%

0.623 is the probability that between 800 and 850 files get damaged.

8 0
3 years ago
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