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irina [24]
2 years ago
9

The table below shows elevations of different locations in the world

Mathematics
2 answers:
S_A_V [24]2 years ago
8 0
Positive I think that would be it
Anna11 [10]2 years ago
7 0
Positive, it should be positive
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PROBLEM: Riley has a rectangular shaped patio that is 13 feet long by 15 feet wide. He wants to DOUBLE THE AREA of the patio by
photoshop1234 [79]

Answer:

1) The equation that represents the total area of Riley's proposed ratio is A' = (\sqrt{2}\cdot x)\cdot (\sqrt{2}\cdot y).

2) The length and width of the new patio are approximately 18.4 feet and 21.2 feet, respectively.

Step-by-step explanation:

1) From Geometry we remember that area formula for the rectangle is represented by:

A = x\cdot y (1)

Where:

A - Area, measured in square feet.

x - Length, measured in feet.

y - Width, measured in feet.

From statement we know that Riley wants to double the area, that is:

A' = 2\cdot A (2)

By applying (1) in (2), we get the following expression:

A' = 2\cdot x\cdot y (3)

Given that Riley wants to double the area of the pation by increasing the length and width by the same amount, we can rearrange (3) by algebraic means:

A' = \sqrt{2}\cdot \sqrt{2}\cdot x\cdot y

A' = (\sqrt{2}\cdot x)\cdot (\sqrt{2}\cdot y) (3b)

The equation that represents the total area of Riley's proposed ratio is A' = (\sqrt{2}\cdot x)\cdot (\sqrt{2}\cdot y).

2) If we know that x = 13\,ft and y = 15\,ft, then the length and the width of the new patio are, respectively:

x' = \sqrt{2}\cdot x

x' = \sqrt{2}\cdot (13\,ft)

x' \approx 18.4\,ft

y' = \sqrt{2}\cdot y

y' = \sqrt{2}\cdot (15\,ft)

y' \approx 21.2\,ft

The length and width of the new patio are approximately 18.4 feet and 21.2 feet, respectively.

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