Answer:
27 m^3
Step-by-step explanation:
<span>So we want to know how much ball bearings can be made with 5.24 cm^3 if one ball bearing has a diameter of 1 cm. We know that radius r=d/2=0.5cm So the volume V of one ball bearing is: V=(4/3)*pi*r^3 so V=(4/3)*3.14*(0.5)^3cm^3=0.524cm^3. Now we simply divide the volume of steel by the volume of the ball bearing: 5.24/0.524=10. So we can make 10 ball bearings from 5.24 cm^3 of steel</span>
let the length of each shorter side be x
length of longer side= x+14
2(x+14) + 2x = 48
2x + 28 + 2x = 48
4x + 28 = 48
4x = 48-28
4x = 20
x = 5
shorter side = 5cm
A. The expression given in the question is
c = 6x + (900000/x)
c = (6x^ +900000)/x
I hope that this is the expression that you were looking for.
b. When x = 240, then
c = [6 * (240)^2 + 900000]/ 240
= (6 * 57600) + 900000/240
= (345600 + 900000)/240
= 5190
From the above deduction, it can be concluded that the cost of ordering and storing is 5190. I hope the procedure is clear enough for you to understand.
Answer:
22 =1
Step-by-step explanation:
