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Mrac [35]
2 years ago
14

HELP ASAP with this question.

Mathematics
1 answer:
nataly862011 [7]2 years ago
5 0
If y=4x+2 and x=1, we can get 4*1+2=6 for y, resulting in 1*6+1/6=2+z. Subtracting 2 from both sides, we get 4+1/6=z
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Charlene wants to build a fence around her rectangular garden. The garden measures 20 meters by 60 meters. 
myrzilka [38]
The perimeter because the fence goes AROUND the yard, not in it.

P = 2w + 2l

P = 2(60) + 2(20)

P = 120 + 40

P = 160

Charlene needs 160 meters of fencing material.
3 0
3 years ago
Read 2 more answers
Write an equivalent expression? Explain your reasoning. (t+t+t) +7t-6/(t+t+t)+2t-3
kiruha [24]

Answer:

Step-by-step explanation:

Combine any like terms on each side of the equation: x-terms with x-terms and constants with constants. Arrange the terms in the same order, usually x-term before constants. If all of the terms in the two expressions are identical, then the two expressions are equivalent.

5 0
3 years ago
Read 2 more answers
7 in.
Inessa [10]

Answer:

7 x 7 x 8 = 392

15 x 7 x 7(14 - 7) = 735

735 + 392 = 1,127 in^3 is your answer.

Let's split the figure:

8 0
3 years ago
Write a polynomial in standard form with zeros at -2 and 3 !!!!! PLZ HELP
lara31 [8.8K]

If the zeros are -2 and 3, then the factored form would be

(x+2) and (x-3)  

-2+2 = 0 and 3-3 = 0

A polynomial is written as ax^2 + bx + c

Expand (x+2) (x-3) using FOIL: Multiply each tern in one set of parenthesis by each term in the other set and then simplify by combining like terms:

x*x + x*-3 + 2*x + 2*-3

x^2 -3x + 2x -6

Polynomial in standard form:

x^2 -x -6

3 0
3 years ago
Read 2 more answers
Consider the differential equation <img src="https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%3D6%20y%5E%7
Nutka1998 [239]
As a Bernoulli equation:

x^2\dfrac{\mathrm dy}{\mathrm dx}=6y^2+6xy\iff x^2y^{-2}\dfrac{\mathrm dy}{\mathrm dx}-6xy^{-1}=6

Let z=y^{-1}\implies\dfrac{\mathrm dz}{\mathrm dx}=-y^{-2}\dfrac{\mathrm dy}{\mathrm dx}. The ODE becomes

-x^2\dfrac{\mathrm dz}{\mathrm dx}-6xz=6
x^6\dfrac{\mathrm dz}{\mathrm dx}+6x^5z=-6x^4
\dfrac{\mathrm d}{\mathrm dx}[x^6z]=-6x^4
x^6z=-6\displaystyle\int x^4\,\mathrm dx
x^6z=-\dfrac65x^5+C
z=-\dfrac6{5x}+\dfrac C{x^6}
y^{-1}=-\dfrac6{5x}+\dfrac C{x^6}
y=\dfrac1{\frac C{x^6}-\frac6{5x}}
y=\dfrac{5x^6}{C-6x^5}

With y(3)=6, we get

6=\dfrac{5(3)^6}{C-6(3)^5}\implies C=\dfrac{4131}2

so the solution is

y=\dfrac{5x^6}{\frac{4131}2-6x^5}=\dfrac{10x^6}{4131-12x^5}

which is valid as long as the denominator is not zero, which is the case for all x\neq\sqrt[5]{\dfrac{4131}{12}}.
8 0
3 years ago
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