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jenyasd209 [6]
3 years ago
13

How many grams of lead (ll) chloride are produced from the reaction of 25g of sodium chloride according to the balanced reaction

? Pb(NO3)2 + 2 NaCL = PbCL2 + NaNO3
Chemistry
1 answer:
Natalka [10]3 years ago
7 0

Answer:

The answer to your question is:  25 g of PbCl2

Explanation:

Data

NaCl = 25 g

PbCl₂ = ?

                       Pb(NO3)2 + 2 NaCl ⇒ PbCl2 + NaNO3

MW NaCl = 58.5 g

MW PbCl2 = 277 g

                       2(58.5 g) of NaCl ------------------------  277 g of PbCl2

                       25 g  of NaCl       ------------------------     x

                       x = (25 x 277) / 117

                       x = 25 g

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4 0
3 years ago
I don't know how to do this can I get the answers plz it's due in 1 hour
katrin [286]
Okay, so even if I just gave you the answers, your teacher needs work on it too so it'll be easier/better if I just explain how to do it.
Basically, both sides need to have the same number of molecules. To do this, we make charts. This is the first side of number one:
Na - 1
Mg- 1
F - 2
The subscript gives F two molecules, and the other ones only each have one. This is the second side:
Na- 1
Mg- 1
F- 1
So they're not equal. To fix this, we add coefficients. These are numbers that are going to appear in the front of each compound/element and changes the number of molecules of the WHOLE compound/element. We need two F on the second side, so we'll put a coefficient of 2 in front of NaF. The new chart for the second side is this:
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Now we've fixed the F, but now Na is off! So let's go to the first side again and see what we can do. We can put a 2 in front of the Na. The new chart is this:
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Now both sides are the same. The full new equation is:
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Basically, do this for all of them. Feel free to ask more questions.
4 0
3 years ago
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