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tester [92]
3 years ago
13

What is the [H30+] in a solution with (OH) = 1.0 x 10-12 M?

Chemistry
1 answer:
dezoksy [38]3 years ago
6 0

Answer:

Concentration of hydronium ion, H3O+ is 1x10^-2 M

Explanation:

The following data were obtained from the question:

Concentration of Hydroxide ion, [OH-] = 1.0x10^-12 M

Concentration of hydronium ion, [H3O+] =?

Next, we shall determine the pOH of the solution. This is illustrated below below:

pOH = - Log [OH-]

pOH = - Log 1.0x10^-12

pOH = 12

Next, we shall determine the pH of the solution.

pH + pOH = 14

pOH = 12

pH + 12 = 14

Collect like terms

pH = 14 - 12

pH = 2

Finally, we shall determine the Concentration of hydronium ion, [H3O+] as follow:

pH = - log [H3O+]

pH = 2

2 = - log [H3O+]

- 2 = log [H3O+]

[H3O+] = Antilog (-2)

[H3O+] = 0.01M = 1x10^-2 M

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what is the concentration of hydroxide ions after 50.0 ml of 0.250 m naoh is added to 120 ml of 0.200 m na2so4? please show all
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The concentration of the hydroxide ions after 50 ml of 0.250M NaOH is added to 120ml of 0.200M Na2SO4 is 7.35 x 10^-2 M.

What is meant by concentration?

Concentration is the total amount of solute present in the given volume of solution. this is expressed in terms of molarity, molality, mole fraction, normality etc. The term concentration mostly refers to the solvents and solutes present in the solution.

Concentration of hydroxide ions can be calculated by,

M (OH^-) = V (NaOH) x M (NaOH) / V (total) = 50ml x 0.250M / 50ml + 120ml = 0.0735M = 7.35 x 10^-2 M.

where M (OH^-) = concentration of hydroxide ions, V(NaOH) = volume of NaOH, M(NaOH) = concentration of NaOH.

Therefore, the concentration of the hydroxide ions after 50 ml of 0.250M NaOH is added to 120ml of 0.200M Na2SO4 is 7.35 x 10^-2 M.

To learn more about concentration click on the given link brainly.com/question/17206790

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