All categories

1 year ago

6. The central selenium atom in selenium hexafluo-

1 answer:

5 0

Given what we know, we can confirm that when forming an expanded octet, selenium hexafluo ride will hold 6 pairs of shared electrons around its center selenium atom.

<h3>What is an expanded octet?</h3>

An expanded octet is when an atom can hold more than 8 valence electrons in its outer shell.
This is possible for those elements in period four of the periodic table.
Elements that are capable of this form what we call hypervalent compounds.

Therefore, given that during an expanded octet formation, the central atom is capable of holding more than 8 valence electrons in its outer shell, the central atom of a selenium hexafluo ride compound will have 12 electrons being shared, which results in 6 pairs, making C the correct answer.

To learn more about valence electrons visit:

brainly.com/question/7223122?referrer=searchResults

You might be interested in

I need help with 1,2,3, and 4

Schach [20]

Answer:

Problem 1: 1.85atm

Problem 2: 110mL

Problem 3: 290 mL

Problem 4: 1.14 atm

Explanation:

Problem 1

1. Data

a) P₁ = 3.25atm

b) V₁ = 755mL

c) P₂ = ?

d) V₂ = 1325 mL

r) T = 65ºC

2. Formula

Since the temeperature is constant you can use Boyle's law for idial gases:

$PV=constant\\\\P_1V_1=P_2V_2$

3. Solution

Solve, substitute and compute:

$P_1V_1=P_2V_2\\\\P_2=P_1V_1/V_2$

$P_2=3.25atm\times755mL/1325mL=1.85atm$

Problem 2

1. Data

a) V₁ = 125 mL

b) P₁ = 548mmHg

c) P₁ = 625mmHg

d) V₂ = ?

2. Formula

You assume that the temperature does not change, and then can use Boyl'es law again.

$P_1V_1=P_2V_2$

3. Solution

This time, solve for V₂:

$P_1V_1=P_2V_2\\\\V_2=P_1V_1/P_2$

Substitute and compute:

$V_2=548mmHg\times 125mL/625mmHg=109.6mL$

You must round to 3 significant figures:

$V_2=110mL$

Problem 3

1. Data

a) V₁ = 285mL

b) T₁ = 25ºC

c) V₂ = ?

d) T₂ = 35ºC

2. Formula

At constant pressure, Charle's law states that volume and temperature are inversely related:

$V/T=constant\\\\\\\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$

The temperatures must be in absolute scale.

3. Solution

a) Convert the temperatures to kelvins:

T₁ = 25 + 273.15K = 298.15K

T₂ = 35 + 273.15K = 308.15K

b) Substitute in the formula, solve for V₂, and compute:

$\dfrac{V_1}{T_1`}=\dfrac{V_2}{T_2}\\\\\\\\\dfrac{285mL}{298.15K}=\dfrac{V_2}{308.15K}\\\\\\V_2=308.15K\times285mL/298.15K=294.6ml$

You must round to two significant figures: 290 ml

Problem 4

1. Data

a) P = 865mmHg

b) Convert to atm

2. Formula

You must use a conversion factor.

1 atm = 760 mmHg

Divide both sides by 760 mmHg

$\dfrac{1atm}{760mmHg}=\dfrac{760mmHg}{760mmHg}\\\\\\1=\dfrac{1atm}{760mmHg}$

3. Solution

Multiply 865 mmHg by the conversion factor:

$865mmHg\times \dfrac{1atm}{760mmHg}=1.14atm\leftarrow answer$

3 0

2 years ago

I set up the conversion factor as 1 mol H20 / 18.02 g H2O because?

Andrej [43]

Answer:

How many grams of H2O are in 1.0 mole of H2O?

18.02 grams

The average mass of one H2O molecule is 18.02 amu. The number of atoms is an exact number, the number of mole is an exact number; they do not affect the number of significant figures. The average mass of one mole of H2O is 18.02 grams.

#Yourchuu

8 0

2 years ago

The equilibrium constant, K for the following reaction is 1.16x103 at 228 K. 2NOBr(g)2NO(g) +Br2(g) When a sufficiently large sa

kow [346]

Answer:

dyedifoggj he yhghs fight

7 0

3 years ago

Does entropy increase or decrease in the following processes?

DaniilM [7]

Where are the following answers?

8 0

3 years ago

What is the atomic mass of an atom that has 6 protons, 6 neutrons, and 6 electrons? A) 6 B) 8 C) + 1 D) 12 E) 18

Oksana_A [137]

Answer: The correct answer is Option D.

Explanation:

Atomic mass of an atom is defined as the sum of number of neutrons and number of protons that are present in an atom. It is represented as 'A'.

Atomic number = Number of protons + Number of neutrons

We are given:

Number of protons = 6

Number of neutrons = 6

Number of electrons = 6

Atomic mass = 6 + 6 = 12

Hence, the correct answer is Option D.

6 0

3 years ago