The area of the ellipse
is given by

To use Green's theorem, which says

(
denotes the boundary of
), we want to find
and
such that

and then we would simply compute the line integral. As the hint suggests, we can pick

The line integral is then

We parameterize the boundary by

with
. Then the integral is


###
Notice that
kind of resembles the equation for a circle with radius 4,
. We can change coordinates to what you might call "pseudo-polar":

which gives

as needed. Then with
, we compute the area via Green's theorem using the same setup as before:






Answer:
x=-5, y=-2
Step-by-step explanation:
3x+2y= -19
-3x-5y= 25
Add the two equations together
3x+2y= -19
-3x-5y= 25
------------------
0x -3y = 6
Divide each side by -3
-3y/-3 = 6/-3
y = -2
Now find x
3x+2y = -19
3x +2(-2) =-19
3x-4 = -19
Add 4 to each side
3x -4+4 = -19+4
3x= -15
divide by 3
3x/3 = -15/3
x = -5
Answer:
(3,2)
Step-by-step explanation:
If you graph the equations, they cross at this point.
Answer:
x = 18
Step-by-step explanation:
the sum of any exterior angle is equal to the sum of any two interior angles
3x-11 + 5x+14 = 9x-15
8x + 3 = 9x - 15
3 = x - 15
x = 18