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3 years ago

14

Hi i will be giving brainlist to best answer

1 answer:

Wewaii [24]3 years ago

8 0

The answer should be figure B

this is because when x is 0, the cost of y is 15

(the +15 is called our initial amount it is when x is equal to zero)

from here if you multiply x by 2 the answer is 20 from our equation 10 times 2 is 20

add the 15 and now our y value is 35

this can be seen on that table when x is 2, the y is 35

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Marley runs 5 yards down the track from point A to point B, and then stops and runs

julia-pushkina [17]

Answer:

$\sqrt{61}$ =AC or 7.8102=AC

Step-by-step explanation:

If we connect a line from point A to point C we create a triangle, and we can use pythagorean theorem to find this distance. So the line from point A to point C will be our hypotenuse and the other two distances will be out side lengths.

$5^{2}+6^{2}=AC^{2}$

25+36= $AC^{2}$

61= $AC^{2}$

$\sqrt{61}$ =AC or 7.8102=AC

3 0

3 years ago

I need the answer ASAP please

Nastasia [14]

Answer:

9 - 3=6

Step-by-step explanation:

7 0

2 years ago

PLEASE HELP ME WITH MY GEOMETRY HOMEWORK!!!!

Oduvanchick [21]

I don’t see the question

7 0

2 years ago

Assume that the terminal side of thetaθ passes through the point (negative 12 comma 5 )(−12,5) and find the values of trigonomet

zmey [24]

Answer:

$\sin \theta = \dfrac{5}{13}$ and $\sec \theta = -\dfrac{13}{12}$

Step-by-step explanation:

Assume that the terminal side of thetaθ passes through the point (−12,5).

In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.

Using Pythagoras theorem:

$hypotenuse^2=perpendicular^2+base^2$

$hypotenuse^2=(5)^2+(12)^2$

$hypotenuse^2=25+144$

$hypotenuse^2=169$

Taking square root on both sides.

$hypotenuse=13$

In a right angled triangle

$\sin \theta = \dfrac{opposite}{hypotenuse}$

$\sin \theta = \dfrac{5}{13}$

$\sec \theta = \dfrac{hypotenuse}{adjacent}$

$\sec \theta = \dfrac{13}{12}$

In second quadrant only sine and cosecant are positive.

$\sin \theta = \dfrac{5}{13}$ and $\sec \theta = -\dfrac{13}{12}$

6 0

3 years ago

4,756 rounded to the nearest thousand is

Shalnov [3]

4,756 rounded to the nearest thousand is 5,000.

8 0

3 years ago

Read 2 more answers