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2 years ago

Find the volume of given solid.plz give explaination.

Mathematics

1 answer:

lara31 [8.8K]2 years ago

7 0

Answer:

480 cm^3

Step-by-step explanation:

Total volume is the sum of the volumes of the 3 cuboids.

Cuboid at the bottom:

V = l×b×h

V = 12 × 5 × 4 = 240

Both on top are identical.

Their height is 10-4= 6 cm

Each has volume = 5×4×6 = 120

Total Volume = 240 + 120 + 120

= 480 cm^3

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This table shows the heights of some of the tallest buildings in the United States. Use the table to answer the question.

FromTheMoon [43]

Answer: If they stood end to end they would be 2,489.

Step-by-step explanation: If you add 1,362 and 1,127 it sums up to 2,489.

5 0

2 years ago

HELP!!! Show work!!!!!!

Misha Larkins [42]

A) x^5/6 ≠ 5√6, Because 5 is in numerator & 6 in denominator in exponential expression so it can be in direct expression.

It is False.

b) (16)^1/4 = 2.
It is False

c) a^2/7 + a^4/7 = a^2/7+4/7 = a^6/7
It is False.

d) Here, powers are not equivalent.
Again, It is False

e) (27x^6)^2/3 = 27^2/3 x^12/3
= 9x^4
It is True.

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In short, Your Answer is Option B

14) ∛8x^6
= ∛8 x^6/3
= 2x²
In short, Your Answer would be Option C

Hope this helps!

7 0

2 years ago

Which statement is a correct interpretation of the vertical line test?

Veseljchak [2.6K]

Vertical line is a way to determine whether a functin is a function or not.

5 0

2 years ago

Read 2 more answers

How do I do number 2 ? Someone please helpp w

Alexxandr [17]

Answer:

yes it is a function

Step-by-step explanation:

You have to take the numbers and see if any of them are the same in the X column if their are some of the same numbers you only write the number once. than you connect the numbers to the given output. If any numbers have 2 outputs it is not a function.

7 0

3 years ago

The probability that two people have the same birthday in a room of 20 people is about 41.1%. It turns out that

salantis [7]

Answer:

a) Let X the random variable of interest, on this case we know that:

$X \sim Binom(n=20, p=0.411)$

This random variable represent that two people have the same birthday in just one classroom

b) We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

$P(X\geq 1 ) = 1-P(X$

And we can find the individual probability:

$P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253$

And then:

$P(X\geq 1 ) = 1-P(X$

And since we want the probability in the 3 classes we can assume independence and we got:

$P= 0.99997^3 = 0.9992$

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

Part a

Let X the random variable of interest, on this case we know that:

$X \sim Binom(n=20, p=0.411)$

This random variable represent that two people have the same birthday in just one classroom

Part b

We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

$P(X\geq 1 ) = 1-P(X$

And we can find the individual probability:

$P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253$

And then:

$P(X\geq 1 ) = 1-P(X$

And since we want the probability in the 3 classes we can assume independence and we got:

$P= 0.99997^3 = 0.9992$

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

4 0

3 years ago

Find the volume of given solid.plz give explaination.​

Find the volume of given solid.plz give explaination.