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julsineya [31]
2 years ago
11

Help me with my math quiz from friday 4/1 SHOW STEPS

Mathematics
1 answer:
malfutka [58]2 years ago
8 0

Hie!! I will be solving the questions in the sequence of the attachments.

_______________________________________

4. As line SU and TV are intersecting each other at O.

A.T.Q, ∠UOV = (7x - 4)°

∠SOT = 87°

Then, ∠UOV = ∠SOT {Vertically Opposite Angles}

\rightarrow\sf{7x - 4=87}

\rightarrow\sf{7x =87+4}

\rightarrow\sf{7x =91}

\rightarrow\sf{x =\frac{91}{7}}

\rightarrow\boxed{\bf{x =13}}

_______________________________________

5. radius = 17ft

circumference of circle = 2πr

\rightarrow\sf{circumference=2\times\frac{22}{7}\times17}

\rightarrow\boxed{\bf{circumference=106.8ft}}

_______________________________________

3. ∠1 and ∠2 - add to 180 (linear pair)

∠1 and ∠3 - equal (Vertically Opposite Angles)

∠3 and ∠4 - add to 180 (linear pair)

∠2 and ∠4 - equal (Vertically Opposite Angles)

_______________________________________

2. 160° + (6x - 16)° = 180° (linear pair)

\rightarrow\sf{6x - 16 = 180-160}

\rightarrow\sf{6x - 16 = 20}

\rightarrow\sf{6x = 20+16}

\rightarrow\sf{6x =36}

\rightarrow\sf{x =\frac{36}{6}}

\rightarrow\boxed{\bf{x =6}}

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The weight of crackers in a box is stated to be 16 ounces. The amount that the packaging machine puts in the boxes is believed t
krek1111 [17]

Answer:

99.99% probability that the mean weight of a 50-box case of crackers is above 16 ounces

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 16.15, \sigma = 0.3, n = 50, s = \frac{0.3}{\sqrt{50}} = 0.0424

What is the probability that the mean weight of a 50-box case of crackers is above 16 ounces?

This is 1 subtracted by the pvalue of Z when X = 16. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{16 - 16.15}{0.0424}

Z = -3.54

Z = -3.54 has a pvalue of 0.0001

1 - 0.0001 = 0.9999

99.99% probability that the mean weight of a 50-box case of crackers is above 16 ounces

3 0
3 years ago
Scarlett has x dimes and y quarters, having no less than 16 coins worth at
stepladder [879]

Answer:

20 dimes = 2.00

4 quarters = 1.00

Step-by-step explanation:

2.00 + 1.00 = 3.00

4 0
3 years ago


Eoin plans to purchase 6.50 pounds of cheese that costs $4.75 per pound. He used the following steps to estimate the cost.


kramer
D Because it's the right answer
4 0
3 years ago
Read 2 more answers
Please help it's due in a few minutes ASAP
wariber [46]

Answer:

110cm square

Step-by-step explanation:

Area of trapezium(regardless whatever trapezium)=

1/2 (a+b)(height)=1/2 (9+13)(10)=110cm square

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3 years ago
In rectangle ABCD the measure of AC is 9.5 cm, then the measure of BD is?​
Mariana [72]

Answer:

BD = 9.5 cm

Step-by-step explanation:

The diagonals of a rectangle are congruent , then

BD = AC = 9.5 cm

3 0
3 years ago
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