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julsineya [31]
2 years ago
11

Help me with my math quiz from friday 4/1 SHOW STEPS

Mathematics
1 answer:
malfutka [58]2 years ago
8 0

Hie!! I will be solving the questions in the sequence of the attachments.

_______________________________________

4. As line SU and TV are intersecting each other at O.

A.T.Q, ∠UOV = (7x - 4)°

∠SOT = 87°

Then, ∠UOV = ∠SOT {Vertically Opposite Angles}

\rightarrow\sf{7x - 4=87}

\rightarrow\sf{7x =87+4}

\rightarrow\sf{7x =91}

\rightarrow\sf{x =\frac{91}{7}}

\rightarrow\boxed{\bf{x =13}}

_______________________________________

5. radius = 17ft

circumference of circle = 2πr

\rightarrow\sf{circumference=2\times\frac{22}{7}\times17}

\rightarrow\boxed{\bf{circumference=106.8ft}}

_______________________________________

3. ∠1 and ∠2 - add to 180 (linear pair)

∠1 and ∠3 - equal (Vertically Opposite Angles)

∠3 and ∠4 - add to 180 (linear pair)

∠2 and ∠4 - equal (Vertically Opposite Angles)

_______________________________________

2. 160° + (6x - 16)° = 180° (linear pair)

\rightarrow\sf{6x - 16 = 180-160}

\rightarrow\sf{6x - 16 = 20}

\rightarrow\sf{6x = 20+16}

\rightarrow\sf{6x =36}

\rightarrow\sf{x =\frac{36}{6}}

\rightarrow\boxed{\bf{x =6}}

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Write the equation in slope-intercept form through the point (-4, -7) and is perpendicular to the line y = -(7/4)x + 4 and graph
Scilla [17]

You have to write the equation for a line that crosses the point (-4, -7) and is perpendicular to the line

y=-\frac{7}{4}x+4

When you have to determine a line that is perpendicular to a known line, you have to keep in mind that the slope of the perpendicular line will be the negative inverse of the first one.

If for exampla you have two lines, the first one being:

y_1=mx+b

And the second one, that is perpedicular to the one above:

y_2=nx+c

The slope of the second one is the negative inverse of the first one:

n=-\frac{1}{m}

The slope of the given line y=-7/4+4 is m=-7/4

So the slope of the perpendicular line has to ve the inverse negative of -7/4

\begin{gathered} n=-(-\frac{4}{7}) \\ n=\frac{4}{7} \end{gathered}

Considering it has to pass through the point (-4,-7) and that we already determined its slope, you can unse the point slope formula to determine the equation of the perpendicular line:

y-y_1=m(x-x_1)

replace with the coordinates of the point and the slope and calculate:

\begin{gathered} y-(-7)=\frac{4}{7}(x-(-4)) \\ y+7=\frac{4}{7}(x+4) \\ y+7=\frac{4}{7}x+\frac{16}{7} \end{gathered}

Subtract 7 to both sides of the equation to write it in slope-intercept form:

\begin{gathered} y+7-7=\frac{4}{7}x+\frac{16}{7}-7 \\ y=\frac{4}{7}x-\frac{33}{7} \end{gathered}

Now you can graph both lines

8 0
1 year ago
jada and diego are practing the piano for sn upcoming rehersal the table list the number of minutes each of them practiced in th
Margarita [4]

Answer:

jadas practice time is 168 minutes or 2 hours 48 minutes.  Diegos practice time is 235 minutes or 3 hours 55minutes hope this helps! have a nice day and good luck with your test!

Step-by-step explanation:

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3 years ago
HELP. It’s LOG form. Since were out of school I forgot how I did this and it’s due so it would be a life saver.
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Answer:

see below

Step-by-step explanation:

exponent to log: a^b = c ---> logₐc = b

ie. question 6

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that will get you through questions 1 to 3, 5 to 6, and 8

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remember that:

logₐc + logₐd = logₐ(cd)

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remember change of base is log_{a} b = \frac{log_xb}{log_xa}, this will be useful if you need your calculator since calculators only have base 10 and maybe if your calculator is good enough natural base e

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3 years ago
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zhannawk [14.2K]

Answer: 80% of x = 20

Hope this helps bye

Have a lovely day.

7 0
3 years ago
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galina1969 [7]
5555555.5 × 2 = 11111111
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