Solution:
1) Rewrite it in the form {a}^{2}-2ab+{b}^{2}, where a={d}^{2} and b=4
{({d}^{2})}^{2}-2({d}^{2})(4)+{4}^{2}
2) Use Square of Difference: {(a-b)}^{2}={a}^{2}-2ab+{b}^{2}
{({d}^{2}-4)}^{2}
3) Rewrite {d}^{2}-4 in the form {a}^{2}-{b}^{2} , where a=d and b=2
{({d}^{2}-{2}^{2})}^{2}
4) Use Difference of Squares: {a}^{2}-{b}^{2}=(a+b)(a-b)
{((d+2)(d-2))}^{2}
5) Use Multiplication Distributive Property: {(xy)}^{a}={x}^{a}{y}^{a}
{(d+2)}^{2}{(d-2)}^{2}
Done!
Answer:Look at this list of whole number powers of -2:
(-2)0 = 1
(-2)1 = -2
(-2)2 = 4
(-2)3 = -8
(-2)4 = 16
Step-by-step explanation:
3/8 of the rows are empty. The three rows that are empty (3) would be in the numerator while the total amount of rows (8) would be in the denominator.
<h2><u>
Answer:</u></h2>
x = 3
y = -8
<h2><u>
Step-by-step explanation:</u></h2>
x + y = -5
x - y = 11
Since the y's will cancel out, we don't need to modify the two equations in any way.
Now, just add the two equations.
x + x = 2x
y + (-y) = 0
-5 + 11 = 6
2x = 6
Divide by 2.
x = 3
To find y, plug 3 in as "x" in one of the two equations.
3 + y = -5
y = -8
