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steposvetlana [31]
3 years ago
15

Write the augmented matrix for each system of equations. 9x-4y-5z=9 7x+4y-4z=-1

Mathematics
2 answers:
Masja [62]3 years ago
6 0

Answer:

The augmented matrix is:

\begin{bmatrix}9 & -4 & -5 & |9\\ 7 & 4 & -4 & |-1\end{bmatrix}

Step-by-step explanation:

<u>Augmented matrix:</u>

It is a matrix form of a linear system of equations obtained from the coefficient matrix. It is created by adding an additional column of for the constants on the right hand side of the equal sign.

Here we are given a system of linear equations as:

9x-4y-5z=9

and 7x+4y-4z=-1

Hence, the augmented matrix formed is as follows:

\begin{bmatrix}9 & -4 & -5 & |9\\ 7 & 4 & -4 & |-1\end{bmatrix}

lakkis [162]3 years ago
4 0
\left[\begin{array}{ccc|c}9&-4&-5&9\\7&4&-4&-1\end{array}\right]
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0.15(y-0.2)=2-0.5(1-y)<br><br> The answer is -153/35 I just need to know how to get that
butalik [34]

Answer:

y=-\dfrac{153}{35}.

Step-by-step explanation:

The given equation is

0.15(y-0.2)=2-0.5(1-y)

Using distributive property, we get

0.15(y)+0.15(-0.2)=2-0.5(1)-0.5(-y)

0.15y-0.03=2-0.5+0.5y

0.15y-0.03=1.5+0.5y

Isolate variable terms.

0.15y-0.5y=1.5+0.03

-0.35y=1.53

Divide both sides by -0.35.

y=\dfrac{1.53}{-0.35}

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y=-\dfrac{153}{35}

Therefore, y=-\dfrac{153}{35}.

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