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Komok [63]
3 years ago
12

Im confused with area and finding area​

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
4 0

Answer: area = length x width. Do you have an actual item or space you are trying to find the area for?

Step-by-step explanation:

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On average, it rains 6 out of 25 days in Houston. On how many days can residents expect rain in 1 year?
zysi [14]

Answer:

87.6 out of 365 so 87 days

Step-by-step explanation:

you divide 365 by 25 and multiply that by 6

5 0
3 years ago
The length of a rectangle is one unit more than the width. if the area is 30 square units find the dimensions of the rectanhgle
solmaris [256]
Width = w

Length = w + 1

Area = 30

w(w+1) = 30

w² + w = 30

w² + w - 30 = 0

w² + 6w - 5w - 30 = 0

w(w + 6) -5(w + 6) = 0 

(w + 6)(w - 5) = 0

w = 5 or -6

Since the width cannot be negative, the width is 5 units.

Hence, the width is 5 units and the length is 6 units. 
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3 years ago
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Rzqust [24]
Select D $660 is the answer
4 0
3 years ago
Negative numbers that equal -60? (I need number that multiple That equal -60)
NikAS [45]

Answer:

-5 x -12

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Solve (x + 1)2 – 4(x + 1) + 2 = 0 using substitution.
solniwko [45]

For this case we have to:

Letu = x + 1

So:

u ^ 2-4u + 2 = 0

We have the solution will be given by:

u = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}

Where:

a = 1\\b = -4\\c = 2

Substituting:

u = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (1) (2)}} {2 (1)}\\u = \frac {4 \pm \sqrt {16-8}} {2}\\u = \frac {4 \pm \sqrt {8}} {2}\\u = \frac {4 \pm \sqrt {2 ^ 2 * 2}} {2}\\u = \frac {4 \pm2 \sqrt {2}} {2}

The solutions are:

u_ {1} = \frac {4 + 2 \sqrt {2}} {2} = 2 + \sqrt {2}\\u_ {2} = \frac {4-2 \sqrt {2}} {2} = 2- \sqrt {2}

Returning the change:

2+ \sqrt {2} = x_ {1} +1\\x_ {1} = 1 + \sqrt {2}\\2- \sqrt {2} = x_ {2} +1\\x_ {2} = 1- \sqrt {2}

Answer:

x_ {1} = 1 + \sqrt {2}\\x_ {2} = 1- \sqrt {2}

3 0
3 years ago
Read 2 more answers
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