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Ede4ka [16]
3 years ago
12

Please someone help I really need this answer please anyone please don’t guess please help thank you

Mathematics
1 answer:
yarga [219]3 years ago
8 0

The quadrilaterals are enlarged.

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Step-by-step explanation:

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Jorge is designing a square poster. the poster has an area of 169in^2.what is the length of each side?
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Let \: the \: side \: of \: the \: poster \: be \: x\: (x>0) \\ \Rightarrow {x}^{2} = 169\Leftrightarrow x = 13 \\ \Rightarrow B. \: 13
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I have a slope of -4 (m=-4), would that be negative four over positive one or would that be negative 4 over negative one?
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If you have a slope of -4 then it would be -4/1 because rise/run. If it were -4/-1 then the slope would be 4.
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3 years ago
Steve and Conner together have $60. Steve has $9 more than twice Conner’s amount. How much money does each have?
Lapatulllka [165]

Answer:

Step-by-step explanation:

let a=Ann's amt., b=Betty's amt.

a=2b+9

b+2b+9=60

3b+9-9=60-9

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6 0
3 years ago
Unghiurile ∢AOB, ∢BOC, ∢COD și ∢DOA sunt unghiuri în jurul punctului O, ∢AOB = 80°, ∢BOC = 140° și CO ⊥ OD.
Sonbull [250]

Answer:

a) ∡AOC = 140 °

∡AOD = 40 °

b) ∡AOB = ∡BOC + ∡AOC și ∡BOC = ∡AOC (unghiuri formate din segmentul OC) prin urmare, segmentul OC bisectează ∡AOB

Step-by-step explanation:

a) Calculați măsurile unghiurilor ∢AOC și ∢AOD.

b) Arătați că jumătatea liniei opuse jumătății liniei OC este bisectoarea unghiului ∢AOB

a) Parametrii dați sunt;

∡AOC. ∡BOC. ∡COD și ∡DOA sunt unghiuri în jurul circumferinței unui cerc

∡AOB = 80 ° și ∡BOC = 140 °, segmentul CO este perpendicular pe segmentul DO

Prin urmare, avem;

∡AOB + ∡BOC + ∡AOC = 360 ° (Suma unghiurilor într-un punct = 360 °)

∴ ∡AOC = 360 ° - (∡AOB + ∡BOC) = 360 ° - (80 ° + 140 °) = 140 °

  ∡AOC = 140 °

∡BOC + ∡BOD = 180 ° (Suma unghiurilor unui triunghi = 180 °)

∡BOD = 180 ° - ∡BOC = 180 ° - 140 ° = 40 °

∡BOD = 40 °

∡ BOD + ∡AOD = ∡AOB

∡AOD = ∡AOB - ∡BOD = 80 ° - 40 ° = 40 °

∡AOD = 40 °

b) Deoarece avem ∡AOB = ∡BOC + ∡AOC și ∡BOC = ∡AOC = 140 °, avem;

∡AOB = 140 ° + 140 ° = 280 ° = 2 × ∡BOC = 2 × ∡AOC

Prin urmare, segmentul OC bisectează ∡AOB

3 0
3 years ago
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