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Ray Of Light [21]

3 years ago

12

Convert 6.42 kilograms to grams. 0.00642 g 64.2 g 642 g 6,420 g

1 answer:

Katarina [22]3 years ago

4 0

1 kilogram (kg) equals to 1000 grams (g). Since you have 6.42 kilograms, divide 6.42 kilograms to 1000 grams. Your final answer is 6420 grams in total.

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11/14 simplified:

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3 years ago

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Andrews [41]

Answer:

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Step-by-step explanation:

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Which of the following is the inverse of the given function? Y=3x^5-4

lawyer [7]

$y\textrm{ }=\textrm{ }(\frac{x\textrm{ }+\textrm{ }4}{3} )^{\frac{1}{5} }$

Step-by-step explanation:

Given function $y\textrm{ }=\textrm{ }3x^{5}\textrm{ }-\textrm{ }4$

To find an inverse for any given function, which is of the form $y=f(x)$ , always swap $x$ and $y$ in the equation and try to get the form $x=f(y)$ . Now, swapping back $x$ and $y$ , we get the inverse function.

On swapping $x$ and $y$ , we get $x\textrm{ }=\textrm{ }3y^{5}\textrm{ }-\textrm{ }4$

$y\textrm{ }+\textrm{ }4\textrm{ }=\textrm{ }3x^{5}$

$x^{5}\textrm{ }=\textrm{ }\frac{y\textrm{ }+\textrm{ }4}{3}$

$x\textrm{ }=\textrm{ }(\frac{y\textrm{ }+\textrm{ }4}{3} )^{\frac{1}{5} }$

Swapping back $x$ and $y$ , we get $y\textrm{ }=\textrm{ }(\frac{x\textrm{ }+\textrm{ }4}{3} )^{\frac{1}{5} }$

This is the inverse function.

3 0

3 years ago

Let A and B be events with =PA0.7, =PB0.3, and =PA or B0.9. (a) Compute PA and B. (b) Are A and B mutually exclusive? Explain. (

kvasek [131]

Answer:

a) $P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

b) False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

c) False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

Step-by-step explanation:

For this case we have the following probabilities given:

$P(A) = 0.7, P(B) =0.7, P(A \cup B) =0.9$

Part a

We want to calculate the following probability: $P(A \cap B)$

And we can use the total probability rule given by:

$P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

Part b

False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

Part c

False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

4 0

3 years ago

6) The height of any child in Mr. Diaz's kindergarten class is no greater than 46 inches.

kakasveta [241]

Answer:

full arrow going left from 46

Step-by-step explanation:

6 0

3 years ago