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Stolb23 [73]
3 years ago
15

PLEASE HELP, THANK YOU!.. :)

Physics
1 answer:
Firlakuza [10]3 years ago
8 0

Answer:

<u><em>First Reaction:</em></u>

^{234}U  =>  ^{230} Th + ^{4}He

<u><em>Second Reaction:</em></u>

^{230} Th => ^{226} Ra + ^{4}He

<u><em>Combined Reaction:</em></u>

^{234} U  => ^{226}Ra + 2( ^{4} He)

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A particle with kinetic energy equal to 282 J has a momentum of magnitude 26.4 kg · m/s. Calculate the speed (in m/s) and the ma
masha68 [24]

Answer:

v=21.36\,\,\frac{m}{s}\\

m=1.2357\,\,kg

Explanation:

Recall the formula for linear momentum (p):

p = m\,v  which in our case equals 26.4 kg m/s

and notice that the kinetic energy can be written in terms of the linear momentum (p) as shown below:

K=\frac{1}{2} m\,v^2=\frac{1}{2} \frac{m^2\,v^2}{m} =\frac{1}{2}\frac{(m\,v)^2}{m} =\frac{p^2}{2\,m}

Then, we can solve for the mass (m) given the information we have on the kinetic energy and momentum of the particle:

K=\frac{p^2}{2\,m}\\282=\frac{26.4^2}{2\,m}\\m=\frac{26.4^2}{2\,(282)}\,kg\\m=1.2357\,\,kg

Now by knowing the particle's mass, we use the momentum formula to find its speed:

p=m\,v\\26.4=1.2357\,v\\v=\frac{26.4}{1.2357} \,\frac{m}{s} \\v=21.36\,\,\frac{m}{s}

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3 years ago
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lawyer [7]

Answer:

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Explanation:

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Leash a block of 0.5 kg down the entire length of an inclined plane forming a name of 37 ° with the horizontal. Friction with th
castortr0y [4]
The potential energy of the block is given by:
V = m*g*h
m mass
g = 9.81m/s²
h height

The potential energy of a spring is given by:
V = 0.5 * k * x²

k spring constant
x compression of the spring

If the block starts from rest it has potential energy, but no kinetic energy. As it slides down the incline potential energy is converted into kinetic energy. When the block hits the spring the kinetic energy is converted into spring's potential energy. If the spring is fully compressed and the block is at rest again, the block has transferred all its energy into the spring. No energy is lost. So we can write:

m * g * h = 0.5 * k * x²

m = 0.5 kg
g = 9.81 m/s²
h = 2.5m * sin 37° = 1,5 m
x = 0,6 m

Solve for k.

k = 2 * m * g * h / x² = 40.8 N/m
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3 years ago
Help help help help please
eduard

Answer:

The sediment settled with the largest particles at the bottom and the smaller at the top.

3 0
3 years ago
What are the 4 forces that are at work within the nucleus of an atom
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<span>Electromagnetic, Strong Nuclear, Weak Nuclear, and Gravity</span>
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