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SCORPION-xisa [38]
3 years ago
9

Problem 23.5 The electric field strength 1.5 cm from an electric dipole, on the axis of the dipole, is 1.5×105 N/C.

Physics
1 answer:
Nataly [62]3 years ago
3 0

We have that the dipole moment in nCm is considering the <em>parameters </em>

electric field strength 1.5 cm and  the axis of the dipole, is 1.5×105 N/C. is

  • P=112.5nCm

From the question we are told

The electric field strength 1.5 cm from an electric dipole, on the axis of the dipole, is 1.5×105 N/C.

<h3>Electric field</h3>

Generally the equation for the Electric field  is mathematically given as

E=\frac{2P}{4\pi*r^3}\\\\Therefore\\\\P=\frac{ 1.5×10^5*1.5*10^{-3}}{2}\\\\

  • P=112.5nCm

For more information on electric field visit

brainly.com/question/16517842

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