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Ilya [14]
3 years ago
10

A substance is said to hygroscopic if it

Chemistry
1 answer:
Sonja [21]3 years ago
7 0
The answer is the Letter D
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A chlorine Cl and bromine Br atom are adsorbed on a small patch of surface (see sketch at right). This patch is known to contain
MrRissso [65]

Explanation:

It is given that possible number of ways the Cl and Br can be absorbed initially are 100.

S, possible number of ways by which Br can be desorbed is as follows.

                  100 \times 99

Now, we will calculate the change in entropy as follows.

               \Delta S = k_{B} ln (\frac{W}{W_{o}})

where,   k_{B} = Boltzmann constant = 1.38 \times 10^{-23}

             \Delta S = change in entropy

Therefore, we will calculate the change in entropy as follows.

             \Delta S = k_{B} ln (\frac{W}{W_{o}})

                         = 1.38 \times 10^{-23} J/K \times ln (\frac{100}{100 \times 99})

                        = 1.38 \times 10^{-23} J/K \times -4.595

                        = -6.34 \times 10^{-23} J/K

Thus, we can conclude that the change in entropy is -6.34 \times 10^{-23} J/K.

5 0
3 years ago
Consider the dissolution of MnS in water (Ksp = 3.0 × 10–14). MnS(s) + H2O(l) Mn2+(aq) + HS–(aq) + OH–(aq) How is the solubility
Mademuasel [1]

Answer:

The solubility of MnS will decrease on addition of KOH solution.

Explanation:

As per the equation given:

MnS(s)+H_{2}O(l) -->Mn^{+2}(aq)+HS^{-}(aq)+OH^{-}(aq)

On dissolution of MnS in water it gives a basic solution as it gives hydroxide ions.

Now when the we are adding aqueous KOH solution, it will dissociate as:

KOH(aq)--->K^{+}(aq)+OH^{-}(aq)

Thus it will further furnish more hydroxide ion,

This will increase the concentration of hydroxide ions (present of product side), the system will try to decrease its concentration by shifting towards reactant side.

Thus the solubility of MnS will decrease on addition of KOH solution.

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in two of they got harder

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