Answer:
2 Fe 2O 3 + 3 C → 4 Fe + 3 CO 2
Explanation:
yeap
Answer:
Mass = 18.29 g
Explanation:
Given data:
Mass of beryllium needed = ?
Mass of nitrogen = 18.9 g
Solution:
Chemical equation:
3Be + N₂ → Be₃N₂
Number of moles of nitrogen:
Number of moles = mass/molar mass
Molar mass of nitrogen = 28 g/mol
Number of moles = 18.9 g/ 28 g/mol
Number of moles = 0.675 mol
Now we will compare the moles of nitrogen and Be.
N₂ : Be
1 : 3
0.675 : 3/1×0.675 = 2.03 mol
Mass of Be:
Mass = number of moles × molar mass
Mass = 2.03 mol × 9.01 g/mol
Mass = 18.29 g
CH₄(g) + 3 Cl₂(g) → CHCl₃(g) + 3 HCl(g)
From the equation we notice that 1 mole of methane produces 1 mole of chloroform:
16 g Methane → 119.38 g Chloroform
? g Methane → 37.5 g Chloroform
by cross multiplication:
= (16 * 37.5) / 119.38 = 5.0 g methane
Closer is bigger................
