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3 years ago

The product of two consecutive negative integers is 600. What is the value of the lesser integer?

Mathematics

1 answer:

g100num [7]3 years ago

7 0

Answer:

Since is a negative number, so it is on the left of 0 on the number line. 9. ... Sum of and 8 + 8 + 8 Product of and 8 8 8 Now, the required quotient 6. ... Then smaller part (y ) toffees. ... OR Let the two consecutive natural numbers be x and x +. ... So, required number 0 0 600 Thus, 600 is the least square number which is ...

Step-by-step explanation:

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Find the second derivative of f(x)=sec(x).

marysya [2.9K]

The derivative of sec x is equal to sec x tan x. The derivative of the first derivative can be determined using the rule of products. The derivative is equal to sec x sec^2 x + tan x * sec x tan x. The simplified answer is sec^3 x + sec^2 x tan x equal to sec^2 x ( sec x + tanx )

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3 years ago

Read 2 more answers

insurance company checks police records on 559 accidents selected at random and notes that teenagers were at the wheel in 91 of

ss7ja [257]

Answer: $(13.22\%,\ 19.34\%)$

Step-by-step explanation:

Given : Sample space : n= 559

Sample proportion : $\hat{p}=\dfrac{91}{559}=0.162790697674\approx0.1628$

$=16.28\%$

Significance level : $\alpha= 1-0.95=0.05$

Critical value : $z_{\alpha/2}=1.96$

Confidence level for population proportion:-

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.1628\pm (1.96)\sqrt{\dfrac{0.1628(1-0.1628)}{559}}\\\\=0.1628\pm0.030604971367\\\\\approx 0.1628\pm0.0306=(0.1322,\ 0.1934)=(13.22\%,\ 19.34\%)$

Hence, 95% confidence interval for the percentage of all auto accidents that involve teenage drivers.= $(13.22\%,\ 19.34\%)$

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3 years ago

A coat regularly cost $125 is put on sale for $75

Stels [109]

If a coat is regularly $125, and they mark it down to $75, we could figure out how much money was taken off by subtracting $75, from $125

$125 - $75 = $50

So the coats price was cut by $50.

Hope it helps
Please mark brainliest!

7 0

3 years ago

G is the incenter, or point of concurrency, of the angle bisectors of ΔACE.

vova2212 [387]

Answer:

▢ $\overline{DG}$ ≅ $\overline{FG}$

▢ $\overline{DG}$ ≅ $\overline{BG}$

▢ $\overline{GE}$ bisects $\displaystyle ∠DEF$

▢ $\overline{GA}$ bisects $\displaystyle ∠BAF$

Step-by-step explanation:

As you can see, angles $\displaystyle BAF$ and $\displaystyle DEF$ form two half-kites, which you should know have two pairs of congruent sides, therefore segments $\displaystyle GA$ and $\displaystyle GE$ are what you call angle bisectours, which is why segments $\displaystyle FG,$ $\displaystyle DG,$ and $\displaystyle BG$ are congruent.

I am joyous to assist you at any time.

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3 years ago

Which lists all the lines that are parallel to line s?

Marianna [84]

Only lines t,u and v

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