Answer: 90% confidence interval is; ( - 0.0516, 0.3752 )
Step-by-step explanation:
Given the data in the question;
n1 = 72, n2 = 17
P1 = 54 / 72 = 0.75
P2 = 10 / 17 = 0.5882
so
P_good = 0.75
P_bad = 0.5882
standard ERRROR will be;
SE = √[(0.75×(1-0.75)/72) + (0.5882×(1-0.5882)/17)]
SE = √( 0.002604 + 0.01424)
SE = 0.12978
given confidence interval = 90%
significance level a = (1 - 90/100) = 0.1, |Z( 0.1/2=0.05)| = 1.645 { from standard normal table}
so
93% CI is;
(0.75 - 0.5882) - 1.645×0.12978 <P_good - P_bad< (0.75 - 0.5882) + 1.645×0.12978
⇒0.1618 - 0.2134 <P_good - P_bad< 0.1618 + 0.2134
⇒ - 0.0516 <P_good - P_bad< 0.3752
Therefore 90% confidence interval is; ( - 0.0516, 0.3752 )
To factor an expression, first you have to find the GCF or Greatest Common Factor of all of the pieces of the expression.
The GCF of 2y^2 and -4y is 2y
So, to factor this expression, we need to divide all of the pieces of the expression by the GCF.
2y(y-2)
2y^2 - 4y in completely factored form is 2y(y-2)
Answer:
DF = 458
Step-by-step explanation:
In statistics, T-test have an extensive application. T-tests are used in hypothesis testing or inference about the population mean when the population standard deviation is not known. Nevertheless, they are used in making inference in paired samples or dependent samples t-test as well as independent samples.
The degrees of freedom, DF, is a characteristic of the student's t distribution which is used in T-tests. In a simple T-test;
DF = n - 1
where n is the sample size
Given n is 459, DF = 459 - 1 = 458
Therefore, DF = 458
The answer is x=-3 and y=13
