Answer:
700 J
Explanation:
Work = Force * Distance
Work = 350 N * 2 M = 700 J
The door's moment of inertia for rotation about a vertical axis inside the door, 14 cm from one edge is 4.205 kgm².
<h3>
Momnet of inertia about a vertical axis inside the door</h3>
The door's moment of inertia for rotation about a vertical axis inside the door, 14 cm from one edge is calculated as follows;
where;
- I, cm is the moment of inertia about central axis
- d is the distance from the edge
- M is mass of the door
<h3>Moment of inertia</h3>
Thus, the door's moment of inertia for rotation about a vertical axis inside the door, 14 cm from one edge is 4.205 kgm².
The complete question is below;
A 25kg solid door is 220 cm tall, 91 cm wide. What is the door's moment of inertia for rotation about a vertical axis inside the degr, 14 cm from one edge.
Learn more about moment of inertia here: brainly.com/question/14460640
An unbalanced force acting on an object results in the object's motion changing. The object may change its speed (speed up or slow down), or it may change its direction. Friction is a force that resists the motion or the tendency toward motion between two objects in contact with each other.
motion
ideal gas in ball assumed.
warmer = high pressure, ball deformed and stressed, could burst
cooler = low pressure, ball shrinks, could go soft.
ideal gas laws help calculate this