50 points for help on a portfolio!!! and brainliest!!
2 answers:
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Answer:
0.26087 rad/s
Explanation:
mass of the child (m) = 40 kg
velocity (v) = 3 m/s
distance (r) = 1.5 m
moment of inertia (I) = 600 kg.m^{2}
rotational momentum of the child = Iω
where
- moment of inertia of the child (I) =
= 40 x 1.5 x 1.5 = 90 kg/m^{2}
- angular velocity (ω) = velocity / distance = 3 / 1.5 = 2 rad/s
rotational momentum of the child = Iω = 90 x 2 = 180 kg/s
from the conservation of momentum the initial momentum of the child must be the same as the final momentum of the child
initial momentum of the child = final momentum of the child
180 = (90 + 600) ω
180 = 690 ω
ω = 180 / 690 = 0.26087 rad/s