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VLD [36.1K]
3 years ago
6

Subtract the following numbers, using scientific notation and the correct number of significant digits.

Physics
2 answers:
tankabanditka [31]3 years ago
5 0

Answer:

The correct answer is - 6.49 × 10^3 mm.

Explanation:

The correct scientific notation of the given subtraction problem is:

6.94 × 10^3 mm - 4.5 × 10^2 mm = _____.

The correct number of significant digits is

a. 6.94 × 10^3 mm = 3

b. 4.5 × 10^2 mm = 2

So subtracting the 6.94 × 10^3 mm - 4.5 × 10^2 mm

= 6940 - 450

= 6.49× 10^3 mm.

xxMikexx [17]3 years ago
4 0

Answer:

6.5x 10^3 mm

Explanation:

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Answer:

Observation 1 represents a solar wind because solar winds are a continuous stream of particles given off by the sun.

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The ratio of output force to input force of a machine it its
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Mechanical advantage is the ratio of output force to input force of a machine.

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3. Which vehicle has more momentum? *
AysviL [449]

Answer:

the one with v = 25 m/s

Explanation:

Momentum = m * v

 if they both have the same mass (15000 kg) , then the one with the higher v has more momentum...I think A= 25 m/s

5 0
2 years ago
The acceleration of gravity on the moon is about 1.6 m/sec 2. An experiment to test gravity compares the time it takes objects t
Valentin [98]
The answer is <span>b. 6.1 times as long
</span>
Step 1: Calculate the time <span>it takes objects to reach a speed on the Moon.
</span>Step 2: Calculate the time it takes objects to reach a speed on the Earth.
Step 3. Divide the time on the Moon by the time on the Earth.

Use the formula: v2 = v1 + at
v2 - the final velocity
v1 - the initial velocity
a - gravitational acceleration
t - time

Step 1.
Moon:
<span>v1 = 0 (because it is free fall)
v2 = 10 m/s
a = 1.6 m/s</span>²
t = ?
______
v2 = v1 + at
10 = 0 + 1.6t
10 = 1.6t
t = 10/1.6
t = 6.25 s


Step 2.
Earth:
v1 = 0 (because it is free fall)
v2 = 10 m/s
a = 9.81 m/s²
t = ?
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v2 = v1 + at
10 = 0 + 9.81t
10 = 9.81t
t = 10/9.81
t = 1.02 s


Step 3:
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7 0
3 years ago
A slender rod 100.00cm long is used as a meter stick. Twoparallel axes which are perpendicular to the rod are considered.The fir
vredina [299]

Answer:

 I /I_{cm}  = 1.48 ,    The correct answer is d

Explanation:

the moment of inertia is given by

        I = ∫ r² dm

For figures with symmetry it is tabulated.   In the case of a thin variation, the moment of inertia with respect to its center of mass is

       I_{cm} = 1/12 M L2

There is a widely used theorem, which is the parallel axis theorem, where the moment of inertia of any parallel axis, is the moment of mass inertia plus the moment of inertia of the body taken as a particle

      I = I_{cm}  + M D²

Let's put these expressions to our case.

As the bar is one meter long its center of mass that this Enel midpoint corresponds to

      I_{cm}  = 1/12 m L²

      I_{cm}  = 1/12 m 1.00²

      I_{cm}  = 8.33 10⁻² m

Let's use the parallel axes theorem for the axis that passes through x = 30 cm.  The distance from the enrode masses to the axis is

       D = x_{cm}  - 0.30

       D = 0.50 - 0.30 = 0.20 m

       I = I_{cm}  + m D²

       I = 8.33 10⁻² m + m 0.2²

       I = (8.33 10⁻² + ​​4 10⁻²) m    

       I = 12.33 10⁻² m

The relationship between these two moments of inertia

       I /I_{cm}  = 12.333 10⁻² / 8.333 10⁻²

       I /I_{cm}  = 1.48

The correct answer is d

3 0
3 years ago
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