Answer:
n = 1.5
Explanation:
The speed of light in vacuum is 300000000 m/s
The speed of light in glass is 200000000 m/s
We need to find the refractive index of the glass.
We know that, the ratio of speed of light in vacuum to the speed of light in medium is equal to refractive index of the medium.
So, the refractive index of the glass is 1.5.
The question is incomplete, we can notice that from from () in between the question.
The correct question is:
A particle of charge on the y-axis a distance a from the origin and a second particle of charge is on the x-axis a distance d from the origin. The magnitude of the x-component of the force on the second particle is:
Answer:
d=
Explanation:
given
distance from origin on y axis = a
distance from origin on x axis = d
attached is an equation that further explains how we got the answer
Explanation:
The given data is as follows.
Magnetic field strength (B) = 0.65 T
Speed (v) = 2.3 m/s
Induced emf (E) = ?
Formula for emf induced at the ends of the rod of length L which is moving with a speed of v is as follows.
E = BvL
Putting the given values into the formula as follows.
=
= 1.495 L .............. (1)
When magnetic field is changed to = 0.48 T
Now, we assume that the speed be to get the emf .
Then,
= 3.11 m/s
Therefore, we can conclude that the speed v of the rod be adjusted to reestablish the emf induced between the ends of the rod at its initial value is 3.11 m/s.
Average velocity has two parts: Its magnitude (size) and its direction.
Its magnitude is
(straight-line distance between start-point and end-point, regardless of the route that's actually followed from start to finish) divided by (time taken to travel from start to finish).
Its direction is
(direction from start-point to end-point)
Notice that straight from this definition, the average velocity of going around a full circle is zero, no matter how fast you traveled. That's because the size of the average velocity is calculated from the straight-line distance from start-point to end-point, and that's zero if you finish at the same point you started from.
Answer:
Explanation:
We are given that a parallel- plate capacitor is charged to a potential difference V and then disconnected from the voltage source.
1 m =100 cm
Surface area =S=
We have to find the charge Q on the positive plates of the capacitor.
V=Initial voltage between plates
d=Initial distance between plates
Initial Capacitance of capacitor
Capacitance of capacitor after moving plates
Potential difference between plates after moving
Hence, the charge on positive plate of capacitor=