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VLD [36.1K]
3 years ago
6

Subtract the following numbers, using scientific notation and the correct number of significant digits.

Physics
2 answers:
tankabanditka [31]3 years ago
5 0

Answer:

The correct answer is - 6.49 × 10^3 mm.

Explanation:

The correct scientific notation of the given subtraction problem is:

6.94 × 10^3 mm - 4.5 × 10^2 mm = _____.

The correct number of significant digits is

a. 6.94 × 10^3 mm = 3

b. 4.5 × 10^2 mm = 2

So subtracting the 6.94 × 10^3 mm - 4.5 × 10^2 mm

= 6940 - 450

= 6.49× 10^3 mm.

xxMikexx [17]3 years ago
4 0

Answer:

6.5x 10^3 mm

Explanation:

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An airplane is flying at 300 mi/h at 4000 m standard altitude. As is typical, the air velocity relative to the upper surface of
posledela

Answer:

57330.17766 Pa

Explanation:

P_1 = Pressure at 4000 m = 61660 Pa

\rho = Density at 4000 m = 0.8194 kg/m³

(Values taken from table of properties of air)

V_1 = Velocity of jet = 300\times \frac{1609.34}{3600}=134.11\ m/s

V_2 = Velocity at max thickness

V_2=1.26V_1=1.26\times 134.11=168.9786\ m/s

From Bernoulli's equation

P_1+\frac{1}{2}\rho V_1^2=P_2+\frac{1}{2}\rho V_2^2\\\Rightarrow P_2=P_1+\frac{1}{2}\rho V_1^2-\frac{1}{2}\rho V_2^2\\\Rightarrow P_2=61660+\frac{1}{2}\times 0.8194\times 134.11^2-\frac{1}{2}\times 0.8194\times 168.9786^2\\\Rightarrow P_2=57330.17766\ Pa

The absolute pressure at this point on the wing is 57330.17766 Pa

3 0
4 years ago
A 50 Q resistor in a circuit has a current flowing through it of 2.0 A. What is
Alex17521 [72]

Hello!

We can use the following equation for calculating power dissipated by a resistor:
P = i^2R

P = Power (? W)
i = Current through resistor (2.0 A)
R = Resistance of resistor (50Ω)

Plug in the known values and solve.

P = (2.0^2)(50) = \boxed{\text{ B. }200 W}

7 0
2 years ago
A 220g mass is on a frictionless horizontal surface at the end of a spring that has a force constant of 7.0N/m The mass is displ
sladkih [1.3K]

Answer:

Explanation:

Your numbers seem wonky, so I'll just assume that the initial displacement is a distance A (Amplitude) from the equilibrium position. Spring constant = k

Initial potential energy is

PE = ½kA²

As potential energy and kinetic energy are constantly exchanging in SHM,

the position x where half of the original spring potential exists is found where

½kx² = ½(½kA²)

    x² = ½A²

    x = (√0.5)A

    x ≈ 0.707A

just plug in your actual starting position A

With A = 5.2 cm

x = 3.67695... 3.7 cm

5 0
3 years ago
Topic: Chapter 10: Projectory or trajectile?
Charra [1.4K]

Answer:

The other angle is 75⁰

Explanation:

Given;

velocity of the projectile, v = 10 m/s

range of the projectile, R = 5.1 m

angle of projection, 15⁰

The range of a projectile is given as;

R = \frac{u^2sin(2\theta)}{g}

To find another angle of projection to give the same range;

5.1 = \frac{10^2 sin(2\theta)}{9.81} \\\\100sin(2\theta) = 50\\\\sin(2\theta) = 0.5\\\\2\theta = sin^{-1}(0.5)\\\\2\theta = 30^0\\\\\theta = 15^0\\\\since \ the \ angle \ occurs \ in \ \ the \ first \ quadrant,\  the \ equivalent \ angle \\ is \ calculated \ as;\\\\90- \theta = 15^0\\\\\theta = 90 - 15^0\\\\\theta = 75^0

<u>Check: </u>

sin(2θ) = sin(2 x 75) = sin(150) = 0.5

sin(2θ) = sin(2 x 15) = sin(30) = 0.5

5 0
3 years ago
What impulse occurs when an average force of 20-N is applied by a dad to a new bike riding child for 3.5 s. b) What change in mo
garri49 [273]

Answer:

A. 70 Ns

B. 70 Kgm/s

C. 2.19 m/s

Explanation:

A. Determination of the impulse.

Force (F) = 20 N

Time (t) = 3.5 s

Impulse (I) =?

Impulse (I) = force (F) × time (t)

I = Ft

I = 20 × 3.5

I = 70 Ns

Thus, the Impulse is 70 Ns.

B. Determination of the change in momentum

Force (F) = 20 N

Time (t) = 3.5 s

Change in momentum =?

Change in momentum = m(v – u) = Ft

Change in momentum = Ft

Change in momentum = 20 × 3.5

Change in momentum = 70 Kgm/s

C. Determination of the final velocity.

Change in momentum = 70 Kgm/s

Initial velocity (u) = 0 m/s

Combined mass (m) = 32 kg

Final velocity (v) =?

Change in momentum = m(v – u)

70 = 32(v – 0)

70 = 32(v)

70 = 32v

Divide both side by 32

v = 70 / 32

v = 2.19 m/s

Thus, the final velocity is 2.19 m/s

3 0
3 years ago
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