Question

write the standard form equation of the line that is parallel to the graph y= X+1 and passes through (0,-2)

Answer 1

The slope of a perpendicular line is the opposite of the given line.

x -> -x

Find a y-intercept that crosses through the point (0, -2).

y = -x - 2 works!

Now change the equation from slope-intercept form to standard form [ Ax + By = C ].

y = -x - 2

y + x = -2

x + y = -2

Best of Luck!

Answer 2

Answer:

$x-y=2$

Step-by-step explanation:

So we want to write the equation of a line that is parallel to y=x+1 and passes through the point (0,-2).

First, parallel lines have the same slope. This means that the slope of our new line must also be 1, the slope of the original line.

Now, to find the equation, we can use the point-slope form. The point-slope form is:

$y-y_1=m(x-x_1)$

Let m (the slope) be 1, and let's let (0,-2) be x₁ and y₁. Thus:

$y-(-2)=1(x-0)$

Simplify:

$y+2=x$

Now, we want the equation to be in standard form. The standard form is:

$Ax+By=C$

Where A, B, and C are integers, and A is positive.

So, subtract x from both sides:

$-x+y+2=0$

Subtract 2 from both sides:

$-x+y=-2$

And, A should be positive, so multiply both sides by -1:

$x-y=2$

And we're done!