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dlinn [17]
3 years ago
13

One megabyte is approximately __________.

Computers and Technology
2 answers:
ArbitrLikvidat [17]3 years ago
4 0
One thousand bites? That's my guess anyway, seems to make the most sense.
denis23 [38]3 years ago
4 0

Answer:

1 million megabytes.

Explanation:

One megabyte is about 1 million bytes (or about 1000 kilobytes).

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Which precaution should you take while working on a computer
Ksivusya [100]

Answer: Maintain a cool temperature to avoid sweating

Explanation:

7 0
3 years ago
Given code:public abstract class A{ }public class B extends A{}The following code sequence would correctly create an object refe
kondaur [170]

Answer:

True.

Explanation:

In the code given in the question we have an abstract class A.Then we have a class B which inherits the class A it is also an example of single inheritance.

Line A c; creates a reference of A type.

Line c=new B(); states that the reference of A type will refer to an object of class B.

Hence we conclude that the answer is True.

6 0
4 years ago
A Uniform Resource Locator (URL) consists of three separate parts: network protocol, host, and web browser.
FrozenT [24]
That is false. are you doing it on a computer course.                                             <span />
3 0
4 years ago
Read 2 more answers
If you look at a white object through a glass of any color, it must appear to remain white.
vodomira [7]
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4 0
3 years ago
Design and implement an algorithm that gets as input a list of k integer values N1, N2,..., Nk as well as a special value SUM. Y
satela [25.4K]

Answer:

Follows are the code to this question:

def FindPair(Values,SUM):#defining a method FindPair  

   found=False;#defining a boolean variable found

   for i in Values:#defining loop for check Value  

       for j in Values:#defining loop for check Value

           if (i+j ==SUM):#defining if block that check i+j=sum

               found=True;#assign value True in boolean variable

               x=i;#defining a variable x that holds i value

               y=j;#defining a variable x that holds j value

               break;#use break keyword

       if(found==True):#defining if block that checks found equal to True

           print("(",x,",",y,")");#print value

       else:#defining else block

           print("Sorry there is no such pair of values.");#print message

Values=[3,8,13,2,17,18,10];#defining a list and assign Values

SUM=20;#defining SUM variable

FindPair(Values,SUM);#calling a method FindPair

Output:

please find the attachment:

Explanation:

In the above python code a method, "FindPair" is defined, which accepts a "list and SUM" variable in its parameter, inside the method "found" a boolean variable is defined, that holds a value "false".

  • Inside the method, two for loop is defined, that holds list element value, and in if block, it checks its added value is equal to the SUM. If the condition is true, it changes the boolean variable value and defines the "x,y" variable, that holds its value.
  • In the next if the block, it checks the boolean variable value, if the condition is true, it will print the "x,y" value, otherwise, it will print a message.  

6 0
3 years ago
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