Answer:
C, Both of these.
Explanation:
You can take notes either way. It's just your preference. Hope this helps :)
Answer:
Printed
Explanation:
The job was finished and sent to the printer. In the printer, you have to waite to be printed
Answer:
Explanation:
.1 Display all information from the customer table for all customers that have a balance that is greater than the average balance.
2. Display all information from the rep table for all representatives that have a rate which is equal to the minimum rate for representatives.
3. Display each unique description and price (no duplicates) for all parts that have a quoted price that is greater than the average quoted price for all parts ordered.
4. List all streets where either a customer or a representative is located
Answer:
// here is code in c++ to find the approx value of "e".
#include <bits/stdc++.h>
using namespace std;
// function to find factorial of a number
double fact(int n){
double f =1.0;
// if n=0 then return 1
if(n==0)
return 1;
for(int a=1;a<=n;++a)
f = f *a;
// return the factorial of number
return f;
}
// driver function
int main()
{
// variable
int n;
double sum=0;
cout<<"enter n:";
// read the value of n
cin>>n;
// Calculate the sum of the series
for (int x = 0; x <= n; x++)
{
sum += 1.0/fact(x);
}
// print the approx value of "e"
cout<<"Approx Value of e is: "<<sum<<endl;
return 0;
}
Explanation:
Read the value of "n" from user. Declare and initialize variable "sum" to store the sum of series.Create a function to Calculate the factorial of a given number. Calculate the sum of all the term of the series 1+1/1!+1/2!.....+1/n!.This will be the approx value of "e".
Output:
enter n:12
Approx Value of e is: 2.71828
