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My name is Ann [436]
3 years ago
15

DUE IN 20 MINS

Mathematics
2 answers:
kherson [118]3 years ago
6 0
The answer would be A!
Vedmedyk [2.9K]3 years ago
4 0

Answer:bellow hope I helped most likely c

Step-by-step explanation:

If 2% per year

480 x 1.02 = 489.6 first year

489.6 x 1.02= 499.392. Second year

499.392 x 1.02 = 509.37984 third year

If 2 % per all 3 years

480 x 1.02 = 489.6 all 3 years

If 2 % per each month

480 x 1.02 = 489.6 first month

489.6 x 1.02 = 499.392 second month

499.392 x 1.02 = 509.37984 third month

509.37984 x1.02 = 519.5674368 forth month

519.5674368 x1.02 =529.958785536 fifth month

529.958785536 x 1.02 =540.5579612467 sixth month

540.5579612467 x 1.02 = 551.3691204716 seventh month

551.3691204716 x 1.02 =562.396502881 eigth month

562.396502881xl x1.02 = 573.6444329386 nineth month

573.6444329386 x 1.02 =

585.1173215974 tenth month

585.1173215974 x 1.02= 596.8196680293 11th month

596.8196680293 x 1.02=608.7560613899 12 months (1 year)

608.7560613899 x1.02 = 620.9311826177 1st month 2nd year

620.9311826177 x 1.02= 633.3498062701 2nd month 2nd year

633.3498062701 x 1.02 = 646.0168023955 3rd month 2nd year

646.0168023955 x 1.02 =658.9371384434 4th month 2nd year

658.9371384434 x 1.02= 672.1158812123 5th month 2nd year

672.1158812123 x1.02 = 685.5581988365 6th month 2nd year

685.5581988365 x 1.02 =699.2693628132 7 th month 2nd year

699.2693628132 x1.02 =713.2547500695 8th month 2nd year

713.2547500695 x 1.02 =727.5198450709 9th Month 2nd year

727.5198450709 x 1.02 =742.0702419723 10th Month 2nd year

742.0702419723 x 1.02 =756.9116468117 11 th month 2nd year

756.9116468117 x 1.02 = 772.0498797479 12th month 2nd year (2 years)

772.0498797479 x 1.02 = 787.4908773429 1st month 3rd year

787.4908773429 x 1.02 =803.2406948898 2nd month 3rd year

803.2406948898 x 1.02 = 819.3055087876 3rd month 3rd year

819.3055087876 x 1.02 = 835.6916189634 4th month 3rd year

835.6916189634 x 1.02 =852.4054513427 5th month 3rd year

852.4054513427 x1.02 = 869.4535603696 6th month 3rd year

869.4535603696 x 1.02 =886.842631577 7th month 3rd year

886.842631577 x 1.02= 904.5794842085 8th month 3rd year

904.5794842085 x 1.02 = 922.6710738927 9th month 3rd year

922.6710738927 x 1.02 = 941.1244953706 10th month 3rd year

941.1244953706 x1.02 = 959.946985278 11th month 3rd year

959.946985278 x 1.02 =979.1459249836 12th month 3rd year (3 years)

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Answer:

the nth term of the sequence is a_n=6n+7

Step-by-step explanation:

Given : An arithmetic sequence begins as follows: a_1=13, a_2=19

To find : Which of the following gives the definition of its nth term?

Solution :

The nth term of the A.P is a_n=a+(n-1)d

The first term is a=a_1=13

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Substitute in the formula,

a_n=13+(n-1)6

a_n=13+6n-6

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