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Zolol [24]
3 years ago
13

Simplify. -2xyz(xy 3yz)

Mathematics
1 answer:
vladimir2022 [97]3 years ago
8 0
-2xyz(xy + 3yz) = -2x^2 y^2 z - 6x y^2 z^2
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BRAINLIEST!!<br> 1. Verify which of the following are identities.
grigory [225]

Answer:

both the equations are identities

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The Students' Conjectures Emily and Zach have two different polynomials to multiply: Polynomial product A: (4x2 – 4x)(x2 – 4) Po
noname [10]

Complete Question:

Emily and Zach have two different polynomials to multiply: Polynomial product A: (4x2 – 4x)(x2 – 4) Polynomial product B: (x2 + x – 2)(4x2 – 8x) They are trying to determine if the products of the two polynomials are the same. But they disagree about how to solve this problem.

Answer:

A = B

Step-by-step explanation:

<em>See comment for complete question</em>

Given

A: (4x^2 - 4x)(x^2 - 4)

B: (x^2 + x - 2)(4x^2 - 8x)

Required

Determine how they can show if the products are the same or not

To do this, we simply factorize each polynomial

For, Polynomial A: We have:

A: (4x^2 - 4x)(x^2 - 4)

Factor out 4x

A: 4x(x - 1)(x^2 - 4)

Apply difference of two squares on x^2 - 4

A: 4x(x - 1)(x - 2)(x+2)

For, Polynomial B: We have:

B: (x^2 + x - 2)(4x^2 - 8x)

Expand x^2 + x - 2

B:(x^2 + 2x - x - 2)(4x^2- 8x)

Factorize:

B:(x(x + 2) -1(x + 2))(4x^2- 8x)

Factor out x + 2

B:(x -1) (x + 2)(4x^2- 8x)

Factor out 4x

B:(x -1) (x + 2)4x(x- 2)

Rearrange

B: 4x(x - 1)(x - 2)(x+2)

The simplified expressions are:

A: 4x(x - 1)(x - 2)(x+2) and  

B: 4x(x - 1)(x - 2)(x+2)

Hence, both polynomials are equal

A = B

3 0
3 years ago
I need help with this​
kirill [66]

Answer:

88

Step-by-step explanation:

The triangles are congruent. Also, a triangle has a sum of 180 degrees for its interior angles.

Angles D and A are both unknown.

Angles O and P are both 55.

Angles G and W are both 37.

37+55 = 92

That means there would be 88 degrees left for the unknown angle to get to the total of 180 degrees.

92 + 88 = 180

4 0
2 years ago
How would the expression x^2+27 be rewritten using sum of cubes?
nydimaria [60]
Assuming the square is not a typo, one can write


x^2+27=(x^{2/3})^3+3^3=(x^{2/3}+3)\bigg((x^{2/3})^2-3x^{2/3}+9\bigg)

=(x^{2/3}+3)\bigg(x^{4/3}-3x^{2/3}+9\bigg)
6 0
3 years ago
Solve by Substitution:<br><br> 3x - y = 4<br> y = 6 - 2x
atroni [7]
Substitute 6 - 2x for y in the first equation

3x - (6 - 2x) = 4

5x - 6 = 4

5x = 10

x = 2

Plug 5 for x in either equations (I'll use the second equation)

y = 6 - 2 * 2

y = 6 - 4

y = 2

(2,2) is the solution.
4 0
3 years ago
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