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3 years ago

Which of the following are names for the plane above?

Mathematics

2 answers:

Phoenix [80]3 years ago

8 0

The answer is C. plane j and plane QLM because you need to have at least three points to form a plane and also the letter J is on the diagram but it is not a point or a line.

Llana [10]3 years ago

7 0

Answer:

<h2>C. plane J and plane QLM</h2>

Step-by-step explanation:

Notice that the letter J is on the plane, but it's not a point on the plane, which means it represents the name of the plane.

So, plan J is a name.

We now by definition that we just need three points to graph a plane, that means we also need just three points to name a plane.

Therefore, a second name for this plane could be QLM or LMQ or MQL.

Therefore, the right answer is C., because it includes the right names for the given plane.

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3 years ago

Jason is pulling a box across the room. He is pulling with a force of 19 newtons and his arm is making a 30 angle with the horiz

Cerrena [4.2K]

We are to solve for the vertical and horizontal component of the force he is pulling with.

1. The vertical component of Jason's force is 9.5Newtons.

2.The horizontal component of Jason's force is 2.67Newtons.

3. Therefore, the net force in the vertical direction is -12.5Newtons.

4.Therefore, Resultant, R is 72.11

Question 1:

If Jason is pulling with a force of 19 Newtons and his arm is at an angle of 30° with the horizontal.

By resolving Jason's force of pull in the vertical direction, Fy = 19 × Sin 30° = 9.5 Newtons.

The vertical component of Jason's force is 9.5 Newtons.

Question 2:

Also,If Jason is pulling with a force of 14 Newtons and his arm is at an angle of 79° with the horizontal.

By resolving Jason's force of pull in the horizontal direction, Fx = 14 × Cos79° = 2.67 Newtons.

The horizontal component of Jason's force is 2.67Newtons.

Question 3:

If Jason is pulling with a force of 23Newtons and his arm is at an angle of 30° with the horizontal.

By resolving Jason's force of pull in the vertical direction, Fy = 23 × Sin 30° = 11.5Newtons.

The vertical component of Jason's force of pull is, 11.5Newtons.

If the box weighs 24Newtons.

By treating up as the +ve vertical direction and down as the -ve vertical direction,

Therefore, the weight of the box acts in the -ve vertical direction, while Jason's vertical force component acts in the +ve vertical direction.

Therefore, the net force in the vertical direction is = 11.5Newtons + (-24Newtons)

Therefore, the net force in the vertical direction is -12.5Newtons.

Question 4:

If there are two forces at right angles to eachother, one of magnitude, 68 and the other of magnitude, 24.

The resultant force on the object can be obtained by Pythagoras theorem (Triangle law of forces).

Resultant, R = √(68²+24²) = √5200.

Therefore, Resultant, R = 72.11

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3 years ago

Read 2 more answers

Luisa buys a plane ticket that has an original price of $\$240$ . She uses a coupon code to get a $30\%$ discount off of the ori

stealth61 [152]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Plz answer ASAP with work ty!

horsena [70]

Answer: $8\sqrt{6}$

Step-by-step explanation:

$\frac{2^4\sqrt{3}}{\sqrt{2}}$

$2^{\frac{7}{2}}\sqrt{3}$

$2^{\frac{7}{2}}=2^{3+\frac{1}{2}}$

$2^3\cdot \:2^{\frac{1}{2}}$ =

$2^3\sqrt{2}$

= $2^3\sqrt{2}\sqrt{3}$ =

$2^3\sqrt{2\cdot \:3}$

= $2^3\sqrt{6}$

$2^3=8$

Answer- $8\sqrt{6}$

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3 years ago